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[USACO 08DEC]Secret Message
Description Bessie is leading the cows in an attempt to escape! To do this, the cows are sending secret binary messages to each other. Ever the clever ...
分类:其他好文   时间:2017-10-08 22:33:01    阅读次数:235
bzoj 1634: [Usaco2007 Jan]Protecting the Flowers 护花
Description Farmer John went to cut some wood and left N (2 <= N <= 100,000) cows eating the grass, as usual. When he returned, he found to his horror ...
分类:其他好文   时间:2017-10-08 15:33:30    阅读次数:194
算法笔记--强连通分量分解
Kosaraju算法 详见《挑战程序设计竞赛》p320 模板: 例题1:POJ 2186 Popular Cows 代码: #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<cmath ...
分类:编程语言   时间:2017-10-08 14:48:21    阅读次数:241
POJ3264 (RMQのST解法)
For the daily milking, Farmer John's N cows (1 ≤ N ≤ 50,000) always line up in the same order. One day Farmer John decides to organize a game of Ultim ...
分类:其他好文   时间:2017-10-07 21:21:12    阅读次数:207
[BZOJ2591][Usaco 2012 Feb]Nearby Cows
2591: [Usaco 2012 Feb]Nearby Cows Description Farmer John has noticed that his cows often move between nearby fields. Taking this into account, he wan ...
分类:其他好文   时间:2017-10-07 20:38:34    阅读次数:202
洛谷 P2986 [USACO10MAR]伟大的奶牛聚集Great Cow Gat…
题目描述 Bessie is planning the annual Great Cow Gathering for cows all across the country and, of course, she would like to choose the most convenient lo ...
分类:其他好文   时间:2017-10-06 21:58:27    阅读次数:243
BZOJ 3016 [Usaco2012 Nov]Clumsy Cows:贪心
题目链接:http://www.lydsy.com/JudgeOnline/problem.php?id=3016 题意: 给你一个括号序列,问你至少修改多少个括号,才能使这个括号序列合法。 题解: 贪心。 cnt表示当前已经攒了多少个左括号。 从左往右枚举每一个括号: (1)如果为左括号,则cnt ...
分类:其他好文   时间:2017-10-06 18:10:24    阅读次数:180
P1607 [USACO09FEB]庙会班车Fair Shuttle
题目描述 Although Farmer John has no problems walking around the fair to collect prizes or see the shows, his cows are not in such good shape; a full day ...
分类:其他好文   时间:2017-10-06 12:59:47    阅读次数:152
POJ3186 Treats for the Cows —— 区间DP
题目链接:http://poj.org/problem?id=3186 Treats for the Cows Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 6548 Accepted: 3446 Description FJ ...
分类:其他好文   时间:2017-10-06 12:30:32    阅读次数:197
最优比率环
POJ 3621 - Sightseeing Cows 找到一个圈,要求这个圈的点权和/边权和在所有的圈中最大,输出这个比率 设最大比率为ans ,∑V/∑E为一般的圈的比率k 最大的圈的k,即ans,>=所有的圈的k 即ans>=∑V/∑E 变形:∑(ans*E-V) > 0 图中边权改为ans* ...
分类:其他好文   时间:2017-10-03 17:48:52    阅读次数:200
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