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Real-time storage area network
A cluster of computing systems is provided with guaranteed real-time access to data storage in a storage area network. Processes issue request for ban...
分类:Web程序   时间:2014-08-07 12:34:09    阅读次数:437
Is VXLAN the Answer to the Network Virtualization Question?
Network virtualization is a growing topic of interest and for some good reasons as networks scale to meet the challenges of cloud computing they are r...
分类:Web程序   时间:2014-08-06 22:23:52    阅读次数:452
eclipse进程一直提示"computing additional info"的解决办法
eclipse进程一直提示"computing additional info"的解决办法...
分类:系统相关   时间:2014-08-06 14:53:01    阅读次数:225
编码类型
UnicodeUnicode is a computing industry standard allowing computers to consistently represent and manipulate text expressed in most of the world's writ...
分类:其他好文   时间:2014-08-01 15:33:42    阅读次数:591
Tagging Physical Resources in a Cloud Computing Environment
A cloud system may create physical resource tags to store relationships between cloud computing offerings, such as computing service offerings, storag...
分类:其他好文   时间:2014-08-01 04:50:21    阅读次数:515
sigmoid函数
这个英文资料有它的非常直观明了的介绍,强烈推荐。http://computing.dcu.ie/~humphrys/Notes/Neural/sigmoid.html------------------------------------------Sigmoid函数是一个S型函数. Sigmoid...
分类:其他好文   时间:2014-07-30 00:27:12    阅读次数:590
云计算之后,雾计算开始
吴韧认为,从这个意义讲, 也许所谓的“雾计算”(fog computing),是一个更加贴切的表述,意指由身边设备完成计算。他强调称,,云和雾是相辅相成, 云端无所不能,雾则无处不在,两者间的信息交换不是原始数据而是智能。 把任何数据都放入云端进行处理,需要非常大的带宽和存储支持和非常小的延时,很多...
分类:其他好文   时间:2014-07-28 21:22:44    阅读次数:297
Uniform synchronization between multiple kernels running on single computer systems
The present invention allocates resources in a multi-operating system computing system, thereby avoiding bottlenecks and other degradations that resul...
分类:其他好文   时间:2014-07-28 11:25:00    阅读次数:302
Troubleshooting routing topology based on a reference topology
In one embodiment, a computing device (e.g., border router or network management server) transmits a discovery message into a computer network, such a...
分类:其他好文   时间:2014-07-23 11:40:46    阅读次数:445
c编程实例:809*??=800*??+9*???+1
程序代码:#include#includevoid main(){ int c; int i,j,k; printf("start computing!!!"); for(i=10;i10&&k<100) printf("809*%d=800*%d+9*%d+1\n",i,k,j); } } ...
分类:其他好文   时间:2014-07-22 23:38:07    阅读次数:242
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