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部分 II. 保护web篇
转载:http://www.mossle.com/docs/auth/html/pt02-web.html部分II.保护web篇2012-12-5 23:42:36 org.springframework.security.config.http.HttpSecurityBeanDefinition...
分类:Web程序   时间:2014-12-04 11:45:53    阅读次数:158
Lowest Common Ancestor of Two Nodes in a Binary Tree
Reference:http://blog.csdn.net/v_july_v/article/details/18312089 http://leetcode.com/2011/07/lowest-common-ancestor-of-a-binary-tree-part-ii.html(1) ....
分类:其他好文   时间:2014-12-04 08:48:25    阅读次数:200
[LeetCode] Jump Game II 贪心
Given an array of non-negative integers, you are initially positioned at the first index of the array.Each element in the array represents your maximu...
分类:其他好文   时间:2014-12-04 06:16:31    阅读次数:240
LeetCode: Combination Sum II 解题报告
Combination Sum IIGiven a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers s...
分类:其他好文   时间:2014-12-03 23:05:22    阅读次数:328
【android基础篇】自定义控件实现一些比较常见的功能
I,我要实现的效果如图所示:当下拉时,显示下拉刷新。松开后,显示松开刷新,接着正在刷新。II,准备工作1)需要自定义ListView,写一个类继承ListView。并在ListView中添加一些数据。 1 private void initView() { 2 listData = new ...
分类:移动开发   时间:2014-12-03 23:02:50    阅读次数:392
LeetCode: Permutations 解题报告
PermutationsGiven a collection of numbers, return all possible permutations.For example,[1,2,3] have the following permutations:[1,2,3], [1,3,2], [2,1...
分类:其他好文   时间:2014-12-03 21:08:41    阅读次数:111
LeetCode: Permutations II 解题报告
Permutations IIGiven a collection of numbers that might contain duplicates, return all possible unique permutations.For example,[1,1,2] have the follo...
分类:其他好文   时间:2014-12-03 20:58:01    阅读次数:185
有趣的乘号金字塔
#includeint main(){int i,n,x,a;scanf("%d",&n);for(i=0;ii;x--){printf(" ");}for(a=1;a<=2*i-1;a++){printf("* ");}printf("\n");}return 0;}
分类:其他好文   时间:2014-12-03 19:01:49    阅读次数:151
微软职位内部推荐-SDE II
微软近期Open的职位:Software Development Engineer II- Commerce Platform GroupStandard job title: Software Development EngineerIIJob posting title: Sr. SDE-ARD...
分类:其他好文   时间:2014-12-03 10:27:39    阅读次数:237
[leetcode]Reverse Linked List II
问题描述: 基本思路: 代码: public ListNode reverse(ListNode head,int n) //Java { ListNode tmp = head; int step = 1; tmp = tmp.next; ListNode pre = head;...
分类:其他好文   时间:2014-12-03 00:29:30    阅读次数:110
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