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windbg定位WEB性能瓶颈案例一则
测试环境服务器:II服务器网站:门户网站条件并发: 2000LoadRunner思考时间:1s表现CPU:100% 对应w3wp进程WebService–>Current connections:2300DB:CPU 10% 无压力压力降低后表现随着并发量下降,CPU 和WebService–>Cu...
分类:数据库   时间:2014-08-08 21:17:46    阅读次数:347
LeetCode "Best Time to Buy and Sell Stock II"
No limit to transaction count, so it is a recursive sum calculation. Take care of boundary condition.class Solution {public: int maxProfit(vector &...
分类:其他好文   时间:2014-08-08 15:58:06    阅读次数:212
Permutations II leetcode java
题目:Given a collection of numbers that might contain duplicates, return all possible unique permutations.For example,[1,1,2] have the following unique....
分类:编程语言   时间:2014-08-08 01:54:55    阅读次数:292
HDU 1165 Eddy's research II (推公式)
Eddy's research IITime Limit: 4000/2000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 3122Accepted Submission(s): 1137...
分类:其他好文   时间:2014-08-07 00:44:57    阅读次数:260
[LeetCode] Unique Binary Search Trees II (难以忍受的递归)
Given n, generate all structurally unique BST's (binary search trees) that store values 1...n.For example, Given n = 3, your program should return all...
分类:其他好文   时间:2014-08-07 00:16:36    阅读次数:276
Spiral Matrix II
问题:蛇形矩阵分析:设置变量dir,0123分别代表方向右下左上class Solution {public: int num[300][300]; void dfs(int x,int y,int k,int n,int dir) { num[x][y]=k; ...
分类:其他好文   时间:2014-08-06 22:25:42    阅读次数:169
Binary Tree Level Order Traversal II
问题:输出二叉树的每一行的结点,从叶子到根/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(i...
分类:其他好文   时间:2014-08-06 22:04:02    阅读次数:185
Pascal's Triangle II
问题:输出杨辉三角的第n行class Solution {public: vector getRow(int rowIndex) { vector vec; int a[100][100]; a[0][0]=1; int j,i; ...
分类:其他好文   时间:2014-08-06 22:03:42    阅读次数:214
Remove Duplicates from Sorted Array II
问题:消除数组中重复次数超过三次的多余的数分析:若ai-1==ai-2若ai也相等,则清楚aiclass Solution {public: int removeDuplicates(int A[], int n) { int i,j; for(i=2;i<n;i+...
分类:其他好文   时间:2014-08-06 21:41:52    阅读次数:199
HDU 4911 水
对于n个数,可以做k次移动,每次移动可以互换相邻位置的两个数,问最少 number of pair (i,j) where 1≤ii>aj. 如果不移动的话,ans=’n个数的逆序对数‘,移动k次会减少k个 归并排序求逆序对数: #include "stdio.h" #include "string.h" #include "math.h" int b[100010],a[1...
分类:其他好文   时间:2014-08-06 14:53:51    阅读次数:211
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