码迷,mamicode.com
首页 >  
搜索关键字:two points    ( 13225个结果
1047. Remove All Adjacent Duplicates In String
Given a string S of lowercase letters, a duplicate removal consists of choosing two adjacent and equal letters, and removing them. We repeatedly make ...
分类:其他好文   时间:2020-02-07 10:42:50    阅读次数:74
leetcode349 350 Intersection of Two Arrays & II
1 """ 2 Intersection of Two Arrays 3 Given two arrays, write a function to compute their intersection. 4 Example 1: 5 Input: nums1 = [1,2,2,1], nums2 ...
分类:其他好文   时间:2020-02-06 23:00:09    阅读次数:74
Codeforces #617 (Div. 3) D. Fight with Monsters(贪心,排序)
There are nn monsters standing in a row numbered from 11 to nn . The ii -th monster has hihi health points (hp). You have your attack power equal to a ...
分类:编程语言   时间:2020-02-06 16:24:55    阅读次数:146
Spark main entry
环境搭建 big data env setup 读写ES spark 怎么读写 elasticsearch Spark 上time series 处理 Flint by Two Sigma ...
分类:其他好文   时间:2020-02-06 14:39:30    阅读次数:66
find min between A[i] + B[j] - K
给两个已经排序好的数组A,B,和一个常数k, 找i,j使得 Ai + Bj - k 的绝对值最小 分析: Two pointer, i从A从前往后扫,j从B从后往前扫.if (A[i]+B[j] > k){ j--;}else { i++;}整个过程不断更新答案 ...
分类:其他好文   时间:2020-02-06 12:27:56    阅读次数:53
1305. All Elements in Two Binary Search Trees
Given two binary search trees root1 and root2. Return a list containing all the integers from both trees sorted in ascending order. Example 1: Input: ...
分类:其他好文   时间:2020-02-06 10:51:59    阅读次数:43
[leetcode]Intersection of Two Arrays
排序。更naive的方法是用set。 class Solution: def intersection(self, nums1: List[int], nums2: List[int]) -> List[int]: result = [] nums1.sort() nums2.sort() i = ...
分类:其他好文   时间:2020-02-06 10:44:04    阅读次数:47
PP: Triple-shapelet networks for time series classification
Problem: time series classification shapelet-based method: two issues 1. for multi-class imbalanced classification tasks, these methods will ignore th ...
分类:Web程序   时间:2020-02-06 01:44:11    阅读次数:127
python-opencv-圆、椭圆与任意多边形的绘制
...
分类:编程语言   时间:2020-02-06 01:31:04    阅读次数:98
leetcode 2 两数之和
https://leetcode-cn.com/problems/add-two-numbers/ ListNode root = new ListNode(0); ListNode cur = root; int retain = 0; while (l1!=null || l2!=null || ...
分类:其他好文   时间:2020-02-05 20:18:39    阅读次数:70
13225条   上一页 1 ... 60 61 62 63 64 ... 1323 下一页
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!