DescriptionGiven a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max sum of a sub-sequence. For example, given (6,-1,5,4,-7), the ma...
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其他好文 时间:
2015-08-13 12:02:10
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82
Could not calculate build plan: Plugin org.apache.maven.plugins:maven-resources-plugin:2.5 or one of解决方法:首先要确保eclipse中maven的配置正确!
找到自己的maven仓库所在的位置,例如我的:C:\Users\liugen.xu.m2\repository\org\apache\mav...
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Web程序 时间:
2015-08-12 19:23:38
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148
DescriptionGiven a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max sum of a sub-sequence. For example, given (6,-1,5,4,-7), the ma...
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其他好文 时间:
2015-08-11 18:12:54
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104
Calculate CAN bit timing parametersCalculate CAN bit timing parameterstypedef struct{ //char name[ 16 ]; // Name of the CAN controller...
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其他好文 时间:
2015-08-11 14:06:47
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362
DescriptionGiven a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max sum of a sub-sequence. For example, given (6,-1,5,4,-7), the ma...
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其他好文 时间:
2015-08-11 09:52:04
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111
分析:注意格式。
#include
int main()
{
int i,j,k;
double sum=0;
printf("n e\n- -----------\n");
printf("0 1\n1 2\n2 2.5\n");
for(i=3;i<=9;i++)
{
k=1;
for(j=1;j<=i;j++)
k*=j;
sum+=1....
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其他好文 时间:
2015-08-10 22:21:47
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112
Description
Given a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max sum of a sub-sequence. For example, given (6,-1,5,4,-7), the max sum in this sequence is 6 + (-1) + 5 + 4 = 1...
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其他好文 时间:
2015-08-10 22:14:59
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163
DescriptionGiven a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max sum of a sub-sequence. For example, given (6,-1,5,4,-7), the ma...
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其他好文 时间:
2015-08-10 21:53:03
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135
Calculate CAN bit timing parametersTSYNC_SEG=== 1TSEG1 = Prop_Seg + Phase_Seg1TSEG2 = Phase_Seg2TBit = TSYNC_SEG + TSEG1 + TSEG2TSEG2 / TBit= Sample P...
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其他好文 时间:
2015-08-10 01:48:01
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503
Calculate S(n).S(n)=13+23 +33 +……+n3 .Input
Each line will contain one integer N(1 < n < 1000000000). Process to end of file.Output
For each case, output the last four dights of S(N) in one line.Samp...
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其他好文 时间:
2015-08-09 18:57:25
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134