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iOS中assign,copy,retain之间的区别以及weak和strong的区别
@property (nonatomic, assign) NSString *title; 什么是assign,copy,retain之间的区别? assign: 简单赋值,不更改索引计数(Reference Counting)。 copy: 建立一个索引计数为1的对象,然后释放旧对象 retai ...
分类:移动开发   时间:2016-03-26 15:29:14    阅读次数:171
【LeetCode】338. Counting Bits (2 solutions)
Counting Bits Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary repres ...
分类:其他好文   时间:2016-03-24 20:03:00    阅读次数:246
leetcode 338. Counting Bits
Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary representation and r
分类:其他好文   时间:2016-03-23 18:27:42    阅读次数:167
LeetCode "Counting Bits"
Neat DP problem to go. If you don't like log(), you can use lookup table.
分类:其他好文   时间:2016-03-21 13:57:56    阅读次数:114
[LeetCode][Java][JavaScript]Counting Bits
Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary representation and r
分类:编程语言   时间:2016-03-19 23:00:17    阅读次数:275
Counting Bits
Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary representation and r
分类:其他好文   时间:2016-03-19 01:03:39    阅读次数:337
Leet Code OJ 338. Counting Bits [Difficulty: Easy]
题目: Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1’s in their binary representation and return them as an array. Example: For num = 5...
分类:其他好文   时间:2016-03-18 21:56:44    阅读次数:208
Parallelogram Counting(平行四边形个数,思维转化)
1058 - Parallelogram Counting PDF (English) Statistics Forum Time Limit: 2 second(s) Memory Limit: 32 MB There are n distinct points in the plane, giv
分类:其他好文   时间:2016-03-09 20:46:08    阅读次数:167
什么是ARC
arc就是自动引用计算。英文名Automatic Reference Counting。在一开始的IOS开发中,内存管理是需要手动的,对某个资源的引用,引用后就对其计算+1,当不再使用就-1,当计算为0,就没有对象引用此资源,就可以释放了。后来呢,大家觉得这样不行,该搞个什么东西自动来做这些事情,当
分类:其他好文   时间:2016-03-06 01:10:34    阅读次数:237
1049 counting ones
从所有一位数包含的1开始向上递推所有k位数包含的1,递推式: ak = ak-1 * 10 + pow(10,k-1); AC代码: #include <vector> #include <cstdio> using namespace std; int main(){ int n; vector<
分类:其他好文   时间:2016-03-03 21:23:27    阅读次数:158
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