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Debugger–veh & she 粗浅一
(我自己使用的"笨办法", 就是 class point + 手动去除 (set/get这类抽象层次很低的函数 + onWin常见消息) + when hit 这样, 通过debug output, dynamic 输出了 call sequence. 但归根到底, 找到准确无误的 call sta...
分类:其他好文   时间:2014-08-22 21:08:19    阅读次数:374
使用jQuery Mobile和Phone Gap开发Android应用程序(转)
经过了一段时间的学习,初步了解了该如何使用jQuery Mobile和 Phone Gap来开发一个Android应用程序,也想把这些东西介绍给大家。1、 软件准备要进行android app的开发,当然需要准备Java, eclipse和安装Android SDK,这个部分网络上面很多方法,搜索“...
分类:移动开发   时间:2014-08-22 12:09:26    阅读次数:254
UVAlive 6763 Modified LCS
LCS stands for longest common subsequence, and it is a well known problem. A sequence in thisproblem means a list of integers, and a sequence X is con...
分类:其他好文   时间:2014-08-22 00:14:45    阅读次数:303
Java Word Ladder(字梯)
问题:Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that:Only one letter...
分类:编程语言   时间:2014-08-21 22:47:14    阅读次数:184
[LeetCode] Count and Say
The count-and-say sequence is the sequence of integers beginning as follows: 1, 11, 21, 1211, 111221, ...1 is read off as "one 1" or 11. 11 is read of...
分类:其他好文   时间:2014-08-21 01:32:23    阅读次数:141
HDU4961:Boring Sum
Problem Description Number theory is interesting, while this problem is boring. Here is the problem. Given an integer sequence a1, a2, …, an, let S(i) = {j|1j is a multiple of ai}. If S(i) is no...
分类:其他好文   时间:2014-08-20 16:34:02    阅读次数:184
编程之美——longest incremental sequence(LIS)
解法一:通过遍历得到(0:i)的LIS,时间复杂度O(N^2);具体思路于代码,如下: 1 #include 2 #include 3 using namespace std; 4 5 int longSub(int arr[],int n); 6 7 int main() 8 { 9 ...
分类:其他好文   时间:2014-08-20 15:44:12    阅读次数:147
oracle 手动增加序列值
1、select seq_name.nextval from dual; //假设得到结果56562、alter sequence seq_name increment by -5655; //注意是-(n-1)3、select seq_name.nextval from dual;//再查一遍,走...
分类:数据库   时间:2014-08-20 15:41:12    阅读次数:271
【Leetcode】Longest Consecutive Sequence
Given an unsorted array of integers, find the length of the longest consecutive elements sequence.For example,Given [100, 4, 200, 1, 3, 2],The longest...
分类:其他好文   时间:2014-08-20 14:01:12    阅读次数:184
【线段树】HDU 3397 Sequence operation 区间合并
操作 Change operations: 0 a b change all characters into '0's in [a , b] 1 a b change all characters into '1's in [a , b] 2 a b change all '0's into '1's and change all '1's into '0's in [a, b] Out...
分类:其他好文   时间:2014-08-20 12:36:52    阅读次数:392
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