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2014ACM/ICPC亚洲区域赛牡丹江站现场赛-K ( ZOJ 3829 ) Known Notation
Known Notation Time Limit: 2 Seconds      Memory Limit: 65536 KB Do you know reverse Polish notation (RPN)? It is a known notation in the area of mathematics and computer science. It is also k...
分类:其他好文   时间:2014-10-16 03:40:51    阅读次数:191
2014ACM-ICPC牡丹江赛区参赛总结
回来之后就被没写的作业和入党的事情搞得一团糟(出门在外还是带两本书比较好),但还是抽空在下个赛区开赛之前把这篇参赛总结赶出来了。 据一开始的分析牡丹江赛区最强,我们也是紧张的不行,一来一回高昂的路费,揭幕战的压力和比较少的准备时间更让我们压力山大。没办法,只有玩命练,偏偏国庆七场ASC成绩惨淡,8号的gym我还手贱拉了一场爆零专场,队友之间的紧张情绪很快传染,直到走之前一天晚上,我们的状态都不是...
分类:其他好文   时间:2014-10-16 02:21:51    阅读次数:220
2014ACM/ICPC亚洲区域赛牡丹江站现场赛-I ( ZOJ 3827 ) Information Entropy
Information Entropy Time Limit: 2 Seconds      Memory Limit: 65536 KB      Special Judge Information Theory is one of the most popular courses in Marjar University. In this course, there is an...
分类:其他好文   时间:2014-10-16 01:01:15    阅读次数:334
2014ACM/ICPC亚洲区域赛牡丹江站现场赛-A ( ZOJ 3819 ) Average Score
Average Score Time Limit: 2 Seconds      Memory Limit: 65536 KB Bob is a freshman in Marjar University. He is clever and diligent. However, he is not good at math, especially in Mathematical A...
分类:其他好文   时间:2014-10-16 00:48:01    阅读次数:428
ACM学习历程——ZOJ 3829 Known Notation (2014牡丹江区域赛K题)(策略,栈)
DescriptionDo you know reverse Polish notation (RPN)? It is a known notation in the area of mathematics and computer science. It is also known as post...
分类:其他好文   时间:2014-10-16 00:15:21    阅读次数:587
2014ACM/ICPC亚洲区域赛牡丹江站总结
弱菜待成长...
分类:其他好文   时间:2014-10-15 00:46:49    阅读次数:186
2014ACM/ICPC亚洲区域赛牡丹江站D和K题
Known Notation Time Limit: 2 Seconds      Memory Limit: 131072 KB Do you know reverse Polish notation (RPN)? It is a known notation in the area of mathematics and computer science. It is also kn...
分类:其他好文   时间:2014-10-15 00:11:49    阅读次数:297
2014牡丹江K Known Notation
Known NotationTime Limit: 2 Seconds Memory Limit: 65536 KBDo you know reverse Polish notation (RPN)? It is a known notation in the area of mathematic....
分类:其他好文   时间:2014-10-14 23:04:39    阅读次数:220
ZOJ 3829 模拟贪心
2014牡丹江现场赛水题 给出波兰式,判断其是否合法,如果不合法有两种操作: 1:任意位置加一个数字或者操作符 2:任意两个位置的元素对调 贪心模拟即可 先判断数字数是否大于操作符数,若不大于 ans+=sum2-sum1+1;新加入的数字全部放到左端。 然后从左到右遍历一遍,存储到当前位置为止,数字数和sum1,和操作数和sum2 若sum2>=1sum1,优先与队...
分类:其他好文   时间:2014-10-14 16:58:49    阅读次数:170
第39届ACM亚洲区域赛牡丹江赛区赛后总结
2014年10月9日,周五,早晨匆匆忙忙的...
分类:其他好文   时间:2014-10-14 02:01:47    阅读次数:320
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