Sorting It All OutTime Limit:1000MSMemory Limit:10000KTotal Submissions:26876Accepted:9271DescriptionAn ascending sorted sequence of distinct values i...
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其他好文 时间:
2014-07-19 15:03:58
阅读次数:
278
Given an unsorted array of integers, find the length of the longest consecutive elements sequence.For example,Given[100, 4, 200, 1, 3, 2],The longest ...
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其他好文 时间:
2014-07-18 18:17:46
阅读次数:
290
The best way to learn DP from DFS! Nice problem.My intuition is that it can be solved by DFS:class Solution {public: int climbStairs(int n) { ...
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其他好文 时间:
2014-07-18 17:24:53
阅读次数:
188
The Jordan 5 3Lab5 Metallic Silver returns inside a mind-turning new iteration for that Spring/Summer time 2014 season. Getting together the very best...
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其他好文 时间:
2014-07-18 15:25:12
阅读次数:
231
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Description
Problem H: Partitioning by Palindromes
We say a sequence of characters is a palindrome if it is the same written forwards and backwards. For example, 'racecar' is a palindrome,...
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其他好文 时间:
2014-07-18 15:13:10
阅读次数:
266
TryCatch的结构为三个Sequence:-Main(exit on:Success) +try(exit on:Failure) +catch(exit on:Done)*以上做法是以前webMethods对于数据库操作的实现,现在有了JDBC Adapter之后,数据库操作变得简单灵活,因而...
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数据库 时间:
2014-07-18 14:22:24
阅读次数:
293
解题思路:
有m行,每行n个数,从每行中取出一个数相加一起求出sum,这样的sum有n的m次方个。要求的前n个最小的sum值。
第一次使用STL里面的堆,一开始对pop_heap()有点不太理解,后来明白了,比如对数组heap[n],最大下标为n-1建堆,默认的是建立大顶堆,heap[0]是数组中最大的数,写一条pop_heap()语句,就是把heap[0]和
heap[n...
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其他好文 时间:
2014-07-18 14:11:34
阅读次数:
281
Sorting It All Out
Time Limit: 1000MS
Memory Limit: 10000K
Total Submissions: 26866
Accepted: 9267
Description
An ascending sorted sequence of distinct values...
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其他好文 时间:
2014-07-18 11:33:31
阅读次数:
294
E. DivisorsBizon the Champion isn't just friendly, he also is a rigorous coder.Let's define function f(a), where a is a sequence of integers. Function...
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其他好文 时间:
2014-07-18 10:21:31
阅读次数:
269
Common SubsequenceTime Limit:1000MSMemory Limit:10000KTotal Submissions:37551Accepted:15023DescriptionA subsequence of a given sequence is the given s...
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其他好文 时间:
2014-07-18 10:02:42
阅读次数:
169