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Catch That Cow
Farmer John has been informed of the location of a fugitive cow and wants to catch her immediately. He starts at a point N (0 ≤ N ≤ 100,000) on a numb ...
分类:其他好文   时间:2017-04-09 10:44:33    阅读次数:206
bfs Catch That Cow
#include #include #include #include #include using namespace std; #define maxn 100001 int steps=0; int book[maxn]={0}; queueq; void bfs(int a,int b) {... ...
分类:其他好文   时间:2017-04-08 21:29:07    阅读次数:183
BFS(广度优先搜索)
Catch That Cow Farmer John has been informed of the location of a fugitive cow and wants to catch her immediately. He starts at a point N (0 ≤ N ≤ 100 ...
分类:其他好文   时间:2017-04-08 19:40:59    阅读次数:366
链剖-What you are?-大话西游-校内oj2440
This article is made by Jason-Cow.Welcome to reprint.But please post the writer's address. http://www.cnblogs.com/JasonCow/ 链剖+线段树 所以为什么 2017.4.8 C题爆零 ...
分类:其他好文   时间:2017-04-08 16:14:55    阅读次数:304
计算几何-点与多边形的位置判断-zoj1081Points Within
This article is made by Jason-Cow.Welcome to reprint.But please post the writer's address. http://www.cnblogs.com/JasonCow/ 叉积判方向 点积判角度 角度和=0°在外面 否则在里 ...
分类:其他好文   时间:2017-04-08 00:53:39    阅读次数:240
web.py的wsgi分析
首先是这个图 更多的理解参照这个 http://diaocow.iteye.com/blog/1922760 http://python.jobbole.com/84279/ 关于application的代码参照这个 http://www.jb51.net/article/65307.htm ...
分类:Web程序   时间:2017-04-05 21:50:19    阅读次数:149
POJ 3180 The Cow Prom(SCC)
【题目链接】 http://poj.org/problem?id=3180 【题目大意】 N头牛,M条有向绳子,能组成几个歌舞团?要求顺时针逆时针都能带动舞团内所有牛。 【题解】 等价于求点数大于1的SCC数量。 【代码】 ...
分类:其他好文   时间:2017-04-04 16:02:24    阅读次数:154
poj3281 Dining
Dining Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 17181 Accepted: 7607 Description Cows are such finicky eaters. Each cow has a prefer ...
分类:其他好文   时间:2017-04-04 11:39:57    阅读次数:219
算法复习——凸包加旋转卡壳(poj2187)
题目: Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, ...
分类:编程语言   时间:2017-04-03 17:51:41    阅读次数:277
BZOJ 1631: [Usaco2007 Feb]Cow Party
题目链接:http://www.lydsy.com/JudgeOnline/problem.php?id=1631 解:先跑一遍最短路,把所有边都反过来以后,再跑一遍 程序: ...
分类:其他好文   时间:2017-04-03 00:59:23    阅读次数:238
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