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POJ3061---Subsequence(尺取法)
Description A sequence of N positive integers (10 < N < 100 000), each of them less than or equal 10000, and a positive integer S (S < 100 000 000) are given. Write a program to find the minimal lengt...
分类:其他好文   时间:2015-03-30 16:36:02    阅读次数:117
csu 1553: Good subsequence (最长连续子序列)
http://acm.csu.edu.cn/OnlineJudge/problem.php?cid=2071&pid=6题意:有一个由n个数组成的序列 要求出一个满足 max-min#include#include#include#include#include#include#include...
分类:其他好文   时间:2015-03-30 01:11:45    阅读次数:132
Subsequence poj 3061 二分(nlog n)或尺取法(n)
SubsequenceTime Limit: 1000MSMemory Limit: 65536KTotal Submissions: 9236Accepted: 3701DescriptionA sequence of N positive integers (10 2 #include 3 .....
分类:其他好文   时间:2015-03-29 19:29:16    阅读次数:175
Distinct Subsequences
https://leetcode.com/problems/distinct-subsequences/Given a stringSand a stringT, count the number of distinct subsequences ofTinS.A subsequence of a ...
分类:其他好文   时间:2015-03-29 17:45:56    阅读次数:146
湖南多校对抗赛(2015.03.28) G Good subsequence
题意:找到一个序列中极值 6 #include 7 #include 8 #include 9 #include10 #include11 #include12 #include13 #include14 #include15 #include16 #include17 #include18 #in...
分类:其他好文   时间:2015-03-29 09:25:48    阅读次数:120
湖南多校对抗赛(2015.03.28) E Longest Increasing Subsequence Again
题意:给你一个序列,问你删除掉连续的一段,使得剩下的序列的最长上升字串最大,问你这个最大值。解题思路:分段dp, dp[i][0] ,dp[i][1] , 0表示前面没有切过,只能从前一个数的0状态得到,1状态表示前面已经切过了,能从前一个的1状态得到,也能从 在他前面的比他值小的dp[j][0]....
分类:其他好文   时间:2015-03-29 09:24:58    阅读次数:128
中南OJ1551: Longest Increasing Subsequence Again(分块+离散化线段树)
1551: Longest Increasing Subsequence Again Time Limit: 2 Sec  Memory Limit: 256 MB Submit: 29  Solved: 15 [Submit][Status][Web Board] Description Give you a numeric sequence. If you can d...
分类:其他好文   时间:2015-03-28 23:18:21    阅读次数:432
Distinct Subsequences
Distinct Subsequences问题:Given a stringSand a stringT, count the number of distinct subsequences ofTinS.A subsequence of a string is a new string which...
分类:其他好文   时间:2015-03-28 21:45:13    阅读次数:167
poj1458——dp,lcs
poj1458——dp,lcsCommon SubsequenceTime Limit:1000MSMemory Limit:10000KTotal Submissions:40529Accepted:16351DescriptionA subsequence of a given sequence...
分类:其他好文   时间:2015-03-22 01:38:48    阅读次数:140
[POJ] 3061 Subsequence (尺取法)
题目地址:http://poj.org/problem?id=3061方法一:因为元素都大于0,所以维护前缀和sum[i],一定有sum[k]>sum[i](k>i)。这样子序列起点s确定以后,用二分查找确定使序列和不小于s的结尾t的最小值。 时间复杂度o(nlogn)。 1 #include...
分类:其他好文   时间:2015-03-21 11:01:09    阅读次数:109
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