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学习python自动化运维diff-text
1.通过html比较diff_text两文本不同之处#!/usr/bin/envpythonimportdifflibtext1="""text1:Thismoduleprovidesclassesandfunctionsforcomparingsequences.includingHTMLandcontextandunifieddiffs.difflibdocumentv7.4addstring"""text1_lines=text1.splitlines()text2="""text..
分类:编程语言   时间:2015-08-12 19:56:38    阅读次数:201
What's Wrong With Hue Oozie Editor?
First, let’s make the topic clear: Comparing with providing raw Oozie workflow/coordinator xml file, what’s disadvantages to create workflow/coordinator with Hue Oozie Editor? ( The Hue Oozie Editor ve...
分类:其他好文   时间:2015-07-23 13:53:23    阅读次数:140
Comparing randomized search and grid search for hyperparameter estimation
Comparing randomized search and grid search for hyperparameter estimationCompare randomized search and grid search for optimizing hyperparameters of a...
分类:其他好文   时间:2015-06-24 20:35:26    阅读次数:128
LeetCode "Basic Calculator II"
Comparing with the 'I' one, there are two changes:1. if last operator is "+" or "-", we don't evaluate expression2. if last operator is "*" or "/", we...
分类:其他好文   时间:2015-06-22 13:37:36    阅读次数:425
git workflows
https://www.atlassian.com/git/tutorials/comparing-workflowsComparing WorkflowsThe array of possible workflows can make it hard to know where to begin ...
分类:其他好文   时间:2015-05-20 23:44:55    阅读次数:160
C/C++浮点数的比较
原文地址:https://randomascii.wordpress.com/2012/02/25/comparing-floating-point-numbers-2012-edition/[Floating-point] math is hard.Seriously. Each time I t...
分类:编程语言   时间:2015-05-14 13:55:48    阅读次数:355
JS中的“==”符号及布尔值转换规则
JS中的“==”符号及布尔值转换规则what are the rules for how == converts types?关于"=="的比较规则:1. Comparing numbers and strings will always convert the strings to numbers...
分类:Web程序   时间:2015-05-12 20:32:30    阅读次数:118
从FindBugs中学Java【四】
5.TQ_ALWAYS_VALUE_USED_WHERE_NEVER_REQUIRED? 6.TQ_COMPARING_VALUES_WITH_INCOMPATIBLE_TYPE_QUALIFIERS? 7.TQ_EXPLICIT_UNKNOWN_SOURCE_VALUE_REACHES_ALWAYS_SINK? 8.TQ_EXPLICIT_UNKNOWN_SOURCE_VALUE_R...
分类:数据库   时间:2015-04-12 00:11:05    阅读次数:245
Comparing Your Heros拓扑序列的数量
给出N行英雄的比较,每一行包含两个英雄的名字,代表第一个英雄比第二个英雄更受欢迎。英雄的数目不超过16个。问有多少种可能的受欢迎程度的序列满足N行英雄的比较。由于只有英雄数目不超过16个,可以用二进制来解决。x的的位表示还有哪些点没有处理。在这些点中选择一个入度没零的点,求剩下的点可能排列的数目。 ...
分类:其他好文   时间:2015-03-04 22:33:44    阅读次数:147
Comparing the contribution of NBA draft picks(转)
When it comes to theNBA draft, experts tend to argue about a number of things: at whichposition willa player be selected? what is the best draft class...
分类:其他好文   时间:2015-01-27 10:57:46    阅读次数:375
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