You are given an integer array sorted in ascending order (may contain duplicates), you need to split them into several subsequences, where each subseq ...
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编程语言 时间:
2017-09-15 13:33:12
阅读次数:
708
A. Sorting by Subsequences You are given a sequence a1,?a2,?...,?an consisting of different integers. It is required to split this sequence into the m ...
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其他好文 时间:
2017-08-29 14:17:28
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180
You are given a sequence a1,?a2,?...,?an consisting of different integers. It is required to split this sequence into the maximum number of subsequenc ...
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编程语言 时间:
2017-08-25 21:01:04
阅读次数:
780
843A - Sorting by Subsequences 还好之前了解过一点白书上的permutation! 我写的递归,其实很容易直接写成递推啊 1 #include <bits/stdc++.h> 2 using namespace std; 3 const int maxn=1e5+10; ...
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其他好文 时间:
2017-08-25 11:04:49
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224
Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequence of a string is a new string which is formed from t ...
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其他好文 时间:
2017-08-24 10:43:40
阅读次数:
244
思路: 对于每个数,尽量放在已有子序列的后面;如果不能,就创建一个新的子序列。 实现: ...
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其他好文 时间:
2017-08-21 19:41:02
阅读次数:
153
You are given an integer array sorted in ascending order (may contain duplicates), you need to split them into several subsequences, where each subseq ...
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其他好文 时间:
2017-08-17 22:09:12
阅读次数:
156
动归: 状态的加法 分完情况后根据遍历到的点的S的当前字母匹不匹配T的当前字母的问题来进行状态转移: 一维数组. 逆序以保证 f[i][j] = f[i- 1][j - 1] + f[i - 1][j]; 加的是上一层的i- 1 ...
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其他好文 时间:
2017-08-05 21:55:16
阅读次数:
172
Given a string S and a string T, count the number of distinct subsequences of S which equals T. A subsequence of a string is a new string which is for ...
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其他好文 时间:
2017-08-05 18:53:43
阅读次数:
131