Since clone DelphiTcsCDPpro/DE150E/Autocom CDP diagnostic system are respected by a large amount of car/trucks owners, mechanics and technicians.Eobd2...
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Windows程序 时间：
2015-04-23 12:51:36
阅读次数：
1526
题目描述You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent ho...
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编程语言 时间：
2015-04-22 18:27:15
阅读次数：
121
题目：House RobberYou are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constra...
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其他好文 时间：
2015-04-22 17:44:42
阅读次数：
112
思路是通过读取/proc/uptime获得系统启动时长。
使用命令cat /proc/uptime
通过man proc可以看到如下的信息：
/proc/uptime：This file contains two numbers: the uptime of the system (seconds), and the amount of time spent in idle process...
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编程语言 时间：
2015-04-22 00:42:24
阅读次数：
163
You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent house...
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其他好文 时间：
2015-04-21 16:17:04
阅读次数：
122
这题告诉我们，要成为一个优秀的小偷，得懂编程才行。哈哈
You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from
robbing each...
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其他好文 时间：
2015-04-21 00:28:04
阅读次数：
154
There areNgas stations along a circular route, where the amount of gas at stationiisgas[i].You have a car with an unlimited gas tank and it costscost[...
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其他好文 时间：
2015-04-21 00:13:37
阅读次数：
266
题目：
You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent h...
分类：
其他好文 时间：
2015-04-20 18:28:00
阅读次数：
127
You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent house...
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其他好文 时间：
2015-04-20 13:13:33
阅读次数：
122
//在全系1000个学生中，征集慈善捐款当总数达到10万的时候，停止捐款，统计人数，并输出平均捐款数
#include
int main()
{
float sum=0;
float amount;
int count=0;
int i;
for(i=0;i<1000;i++)
{
printf("请输入捐款金额：");
scanf("%f",&amount);
sum=...
分类：
编程语言 时间：
2015-04-17 20:37:28
阅读次数：
171
