1、按单词出现频率降序排序！
2、按字母出现频率降序排序！
the squid project provides a number of resources to assist users design,implement and support squid installations. Please browse the documentation and support sections for more infomation
解答：
cat test.txt
the squid project provides a number of resources to assist users design,implement and support squid installations. Please browse the documentation and support sections for more infomation
按单词排序解答：
法1：
[root@oldboy ~]# awk -F "[,. ]" ‘{for(i=1;i<=NF;i++)array[$i]++}END{for(key in array)print array[key],key|"sort -nr"}‘ oldboy.txt|column -t
2 the
2 support
2 squid
2 and
1 users
1 to
1 sections
1 resources
1 provides
1 project
1 Please
1 of
1 number
1 more
1 installations
1 infomation
1 implement
1 for
1 documentation
1 design
1 browse
1 assist
1 a
1
法2：
[root@MySQL ~]# tr "[ ,.]" "\n"<oldboy.txt|grep -v "^$"|sort|uniq -c|sort -rn
2 the
2 support
2 squid
2 and
1 users
1 to
1 sections
1 resources
1 provides
1 project
1 Please
1 of
1 number
1 more
1 installations
1 infomation
1 implement
1 for
1 documentation
1 design
1 browse
1 assist
1 a
按字母频率排序
法1
[root@MySQL ~]# tr "{ |,|.}" "\n"<oldboy.txt|awk -F "" ‘{for(i=1;i<=NF;i++)array[$i]++}END{for(key in array)print array[key],key|"sort -nr"}‘
19 s
17 e
16 o
14 t
12 n
12 i
11 r
9 a
8 u
7 p
7 d
6 m
4 l
4 c
3 f
2 q
2 h
2 b
1 w
1 v
1 P
1 j
1 g
[root@MySQL ~]# tr "[ ,.]" "\n"<oldboy.txt|awk ‘{for(i=1; i<=length($0); i++) ++S[substr($0,i,1)]} END {for(a in S) print S[a], a|"sort -rn"}‘
19 s
17 e
16 o
14 t
12 n
12 i
11 r
9 a
8 u
7 p
7 d
6 m
4 l
4 c
3 f
2 q
2 h
2 b
1 w
1 v
1 P
1 j
1 g有关AWK数组的超详细案例讲解就在老男孩教育最新高级运维班课程！
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原文地址：http://oldboy.blog.51cto.com/2561410/1686891
