Let A1, A2, ... , AN be N elements. You need to deal with two kinds of operations. One type of operation is to add a given number to a few numbers in a given interval. The other is to query the value of some element.

There are a lot of test cases. 
The first line contains an integer N. (1 <= N <= 50000)
The second line contains N numbers which are the initial values of A1, A2, ... , AN. (-10,000,000 <= the initial value of Ai <= 10,000,000)
The third line contains an integer Q. (1 <= Q <= 50000)
Each of the following Q lines represents an operation.
"1 a b k c" means adding c to each of Ai which satisfies a <= i <= b and (i - a) % k == 0. (1 <= a <= b <= N, 1 <= k <= 10, -1,000 <= c <= 1,000)
"2 a" means querying the value of Aa. (1 <= a <= N)

For each test case, output several lines to answer all query operations.

4 
1 1 1 1
14
2 1
2 2
2 3
2 4
1 2 3 1 2
2 1 
2 2
2 3
2 4
1 1 4 2 1
2 1
2 2
2 3
2 4

1
1
1
1
1
3
3
1
2
3
4
1

2012 ACM/ICPC Asia Regional Changchun Online

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#include<iostream>
#include<algorithm>
#include<stdio.h>
#include<string.h>
#include<stdlib.h>

#define N 50010

using namespace std;

int a[N];
int c[N][12][12];
int n,m;

int lowbit(int x) {
    return x&(-x);
}

void updata(int x,int k,int mod,int num) {
    while(x<=n) {
        c[x][k][mod] += num;
        x += lowbit(x);
    }
}

int getsum(int x,int y) {
    int s = 0;
    while(x>0) {
        for(int i=1; i<=10; i++) {
            s += c[x][i][y%i];
        }
        x -= lowbit(x);
    }
    return s;
}
int main() {
    while(scanf("%d",&n)!=EOF) {
        memset(c,0,sizeof(c));
        for(int i=1; i<=n; i++) {
            scanf("%d",&a[i]);
        }
        int x,y,k,num;
        scanf("%d",&m);
        while(m--) {
            scanf("%d",&x);
            if(x == 1) {
                scanf("%d%d%d%d",&x,&y,&k,&num);
                updata(x,k,x%k,num);
                updata(y+1,k,x%k,-num);
            } else {
                scanf("%d",&y);
                int sum = getsum(y,y);
                printf("%d\n",sum+a[y]);
            }
        }

    }
    return 0;
}