Spring Security Web应用入门环境搭建

标签：spring   spring security   登录   

在使用Spring Security配置Web应用之前，首先要准备一个基于Maven的Spring框架创建的Web应用（Spring MVC不是必须的），本文的内容都是基于这个前提下的。

pom.xml添加依赖

除了Spring框架本身的一些依赖包，还需要在pom.xml中添加Spring Security的依赖包：

<dependency>
    <groupId>org.springframework.security</groupId>
    <artifactId>spring-security-web</artifactId>
    <version>4.0.2.RELEASE</version>
</dependency>
<dependency>
    <groupId>org.springframework.security</groupId>
    <artifactId>spring-security-config</artifactId>
    <version>4.0.2.RELEASE</version>
</dependency>

入门环境配置

要想使用Spring Security，首先需要在web.xml配置一个过滤器，注意过滤器的filter-name必须是"springSecurityFilterChain"：

<filter>
    <filter-name>springSecurityFilterChain</filter-name>
    <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
    <filter-name>springSecurityFilterChain</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>

<beans:beans xmlns="http://www.springframework.org/schema/security"
    xmlns:beans="http://www.springframework.org/schema/beans" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://www.springframework.org/schema/beans
        http://www.springframework.org/schema/beans/spring-beans.xsd
        http://www.springframework.org/schema/security
        http://www.springframework.org/schema/security/spring-security.xsd">
 
    <http use-expressions="false">
        <!-- 访问所有页面都需要有USER权限 -->
        <intercept-url pattern="/**" access="ROLE_USER" />
        <!-- 登录功能 -->
        <form-login />
        <!-- 登出功能 -->
        <logout />
    </http>
 
    <authentication-manager>
        <authentication-provider>
            <user-service>
                <!-- 这里创建两个用户，可以通过用户名密码登录 -->
                <user name="jimi" password="jimispassword" authorities="ROLE_USER, ROLE_ADMIN" />
                <user name="bob" password="bobspassword" authorities="ROLE_USER" />
            </user-service>
        </authentication-provider>
    </authentication-manager>
 
</beans:beans>

在登录页面输入错误的用户名密码，就会登录失败并有提示。输入正确的用户名密码，则登录成功，就可以进入Web应用的页面。一个最简单的基于Spring Security的Web应用已经完成！

指定登录页面

由于Spring Security默认的登录页面非常简陋，一般不会直接使用，通常会指定一个自定义的登录页面：

<http use-expressions="false">
    <!-- 登录页面不需要控制权限 -->
    <intercept-url pattern="/login.jsp*" access="IS_AUTHENTICATED_ANONYMOUSLY"/>
    <!-- 访问其他所有页面都需要有USER权限 -->
    <intercept-url pattern="/**" access="ROLE_USER" />
    <!-- 配置登录页面地址login-page、登录失败后的跳转地址authentication-failure-url -->
    <form-login login-page=‘/login.jsp‘ authentication-failure-url=‘/login.jsp?error‘ />
    <!-- 登出功能 -->
    <logout />
</http>

自定义的登录页面jsp中的登录表单：

<c:url value="/login" var="loginUrl" />
<form action="${loginUrl}" method="post">
    <c:if test="${param.error != null}">
        <p>Invalid username and password.</p>
    </c:if>
    <c:if test="${param.logout != null}">
        <p>You have been logged out.</p>
    </c:if>
    <p>
        <label for="username">Username</label>
        <input type="text" id="username" name="username" />
    </p>
    <p>
        <label for="password">Password</label>
        <input type="password" id="password" name="password" />
    </p>
    <input type="hidden" name="${_csrf.parameterName}" value="${_csrf.token}" />
    <button type="submit" class="btn">Log in</button>
</form>

登录表单提交的页面地址是/login，method是POST请求。为了安全，防止恶意的CSRF攻击，Spring Security需要校验form表单中的hidden域提交的内容。

登出

<c:url value="/logout" var="logoutUrl" />
<form action="${logoutUrl}" method="post">
    <input type="hidden" name="${_csrf.parameterName}" value="${_csrf.token}" />
    <input type="submit" value="退出" />
</form>

<authentication-manager>
    <authentication-provider user-service-ref=‘userDetailsService‘ />
</authentication-manager>
<beans:bean id="userDetailsService" class="org.springframework.security.core.userdetails.jdbc.JdbcDaoImpl">
    <beans:property name="dataSource" ref="dataSource"/>
    <beans:property name="usersByUsernameQuery" value="select username, password, true from t_user where username = ?" />
    <beans:property name="authoritiesByUsernameQuery" value="select username, role from t_user_role where username = ?" />
</beans:bean>

<authentication-manager>
    <authentication-provider>
        <jdbc-user-service data-source-ref="dataSource"
            users-by-username-query="select username, password, true from t_user where username = ?"
            authorities-by-username-query="select username, role from t_user_role where username = ?" />
    </authentication-provider>
</authentication-manager>

public class UserDetailsServiceImpl implements UserDetailsService {
 
    @Override
    public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
        // 以下可以替换成用其他方式获取用户信息
        if(username.equals("xxg")) {
            Collection<GrantedAuthority> auths = new ArrayList<GrantedAuthority>();
            SimpleGrantedAuthority authority = new SimpleGrantedAuthority("ROLE_USER"); 
            auths.add(authority);
            User user = new User(username, "123456", auths);
            return user;
        } else {
            throw new UsernameNotFoundException("用户不存在");
        }
    }
}

<authentication-manager>
    <authentication-provider user-service-ref=‘userDetailsService‘ />
</authentication-manager>
<beans:bean id="userDetailsService" class="com.xxg.service.UserDetailsServiceImpl" />

<http pattern="/resources/css/**" security="none"/>
<http pattern="/resources/images/**" security="none"/>
<http pattern="/resources/js/**" security="none"/>
<http use-expressions="false">
    <intercept-url pattern="/**" access="ROLE_USER" />
    <form-login />
    <logout />
</http>

获取登录用户信息

获取用户名：

httpServletRequest.getRemoteUser();  // Servlet标准，推荐使用
SecurityContextHolder.getContext().getAuthentication().getName();

SecurityContextHolder.getContext().getAuthentication().getAuthorities();

httpServletRequest.isUserInRole("ADMIN");

Spring Security Web应用入门环境搭建

标签：spring   spring security   登录   

原文地址：http://blog.csdn.net/xiao__gui/article/details/48241029