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输入一个正整数数组,把数组里所有数字拼接起来排成一个数,打印能拼接出的所有数字中最小的一个。例如输入数组{3,32,321},则打印出这3个数字能排成的最小数字321323.
剑指Offer(纪念版)P177
// int型整数用十进制表示最多只有10位
const int g_MaxNumberLength = 10;
char* g_StrCombine1 = new char[g_MaxNumberLength * 2 + 1];
char* g_StrCombine2 = new char[g_MaxNumberLength * 2 + 1];
void PrintMinNumber(int* numbers, int length)
{
if(numbers == NULL || length <= 0)
return;
char** strNumbers = (char**)(new int[length]);
for(int i = 0; i < length; ++i)
{
strNumbers[i] = new char[g_MaxNumberLength + 1];
sprintf(strNumbers[i], "%d", numbers[i]);
}
qsort(strNumbers, length, sizeof(char*), compare);
for(int i = 0; i < length; ++i)
printf("%s", strNumbers[i]);
printf("\n");
for(int i = 0; i < length; ++i)
delete[] strNumbers[i];
delete[] strNumbers;
}
// 如果[strNumber1][strNumber2] > [strNumber2][strNumber1], 返回值大于0
// 如果[strNumber1][strNumber2] = [strNumber2][strNumber1], 返回值等于0
// 如果[strNumber1][strNumber2] < [strNumber2][strNumber1], 返回值小于0
int compare(const void* strNumber1, const void* strNumber2)
{
// [strNumber1][strNumber2]
strcpy(g_StrCombine1, *(const char**)strNumber1);
strcat(g_StrCombine1, *(const char**)strNumber2);
// [strNumber2][strNumber1]
strcpy(g_StrCombine2, *(const char**)strNumber2);
strcat(g_StrCombine2, *(const char**)strNumber1);
return strcmp(g_StrCombine1, g_StrCombine2);
}
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原文地址:http://www.cnblogs.com/xwz0528/p/4864386.html