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     oracle中, 经常用户的状态会变成locked, expired 等状态, 这种情况下怎么处理呢?
  首先,  如果是locked状态还好办, DBA直接执行alter user scott account unlock 就可以了.
  但是如果变成expired状态, oracle本身是不提供解锁的语句的, 因为账户过期,必须要用户更改密码, 账户才能重新使用. 但有些时候, 因为各种原因, 我们并不知道原密码的明文是什么,这时候就很麻烦了, 经研究发现,有两种方法可以实现:
  一. 用原密码的密文来更改密码:
  [sql] view plaincopyprint?
  01.SQL>conn  /as sysdba
  02.SQL>select password from dba_users where username=‘SCOTT‘;
  03.password
  04.------------------------------
  05.E65E6AF62B2449CF
  06.
  07.SQL>alter user SCOTT identified by values ‘E65E6AF62B2449CF‘;
  SQL>conn  /as sysdba
  SQL>select password from dba_users where username=‘SCOTT‘;
  password
  ------------------------------
  E65E6AF62B2449CF
  SQL>alter user SCOTT identified by values ‘E65E6AF62B2449CF‘;
  这种情况下,虽然我们不知道原密码是什么,但可以用它的密文来更改密码,这样,在不知道原密码的情况下,既保持了密码不改变, 又可以把expired的状态更改掉.
  二.  下面这一条语句搞定,不管用户的状态是什么:
  [sql] view plaincopyprint?
  01.UPDATE USER$ SET ASTATUS=0 WHERE NAME=‘SCOTT‘;
  UPDATE USER$ SET ASTATUS=0 WHERE NAME=‘SCOTT‘;
  原理详解:
  用户的信息都是存在user$这样一个系统表里面的
  [sql] view plaincopyprint?
  01.SQL> select name,ASTATUS,password from user$ where name IN(‘SYS‘,‘SCOTT‘);
  02.
  03.
  04.NAME                              ASTATUS PASSWORD
  05.------------------------------ ---------- ------------------------------
  06.SCOTT                                   1 E65E6AF62B2449CF
  07.SYS                                     0 8A8F025737A9097A
  08.
  09.SQL> select username,account_status from dba_users where username in(‘SYS‘,‘SCOTT‘);
  10.
  11.USERNAME                       ACCOUNT_STATUS
  12.------------------------------ --------------------------------
  13.SYS                            OPEN
  14.SCOTT                          EXPIRED
  SQL> select name,ASTATUS,password from user$ where name IN(‘SYS‘,‘SCOTT‘);
  NAME                              ASTATUS PASSWORD
  ------------------------------ ---------- ------------------------------
  SCOTT                                   1 E65E6AF62B2449CF
  SYS                                     0 8A8F025737A9097A
  SQL> select username,account_status from dba_users where username in(‘SYS‘,‘SCOTT‘);
  USERNAME                       ACCOUNT_STATUS
  ------------------------------ --------------------------------
  SYS                            OPEN
  SCOTT                          EXPIRED
  而用户ASTATUS对应的表为:user_astatus_map
  [sql] view plaincopyprint?
  01.SQL> select * from user_astatus_map;
  02.
  03.   STATUS# STATUS
  04.---------- --------------------------------
  05.         0 OPEN
  06.         1 EXPIRED
  07.         2 EXPIRED(GRACE)
  08.         4 LOCKED(TIMED)
  09.         8 LOCKED
  10.         5 EXPIRED & LOCKED(TIMED)
  11.         6 EXPIRED(GRACE) & LOCKED(TIMED)
  12.         9 EXPIRED & LOCKED
  13.        10 EXPIRED(GRACE) & LOCKED
  14.
  15.9 rows selected.
  SQL> select * from user_astatus_map;
  STATUS# STATUS
  ---------- --------------------------------
  0 OPEN
  1 EXPIRED
  2 EXPIRED(GRACE)
  4 LOCKED(TIMED)
  8 LOCKED
  5 EXPIRED & LOCKED(TIMED)
  6 EXPIRED(GRACE) & LOCKED(TIMED)
  9 EXPIRED & LOCKED
  10 EXPIRED(GRACE) & LOCKED
  9 rows selected.
  关键是user$表本身是可以更改的, 所以此时我们就可以直接把用户的ASTATUS字段改成0就可以了
  [sql] view plaincopyprint?
  01.SQL> UPDATE USER$ SET ASTATUS=0 WHERE NAME=‘SCOTT‘;
  02.1 row updated.
  03.
  04.SQL> COMMIT;
  05.Commit complete.
  06.
  07.SQL> alter system flush shared_pool;
  08.System altered.
  SQL> UPDATE USER$ SET ASTATUS=0 WHERE NAME=‘SCOTT‘;
  1 row updated.
  SQL> COMMIT;
  Commit complete.
  SQL> alter system flush shared_pool;
  System altered.
  再来观察结果:
  [sql] view plaincopyprint?
  01.SQL> select name,ASTATUS,password from user$ where name IN(‘SYS‘,‘SCOTT‘);
  02.
  03.NAME                              ASTATUS PASSWORD
  04.------------------------------ ---------- ------------------------------
  05.SCOTT                                   0 E65E6AF62B2449CF
  06.SYS                                     0 8A8F025737A9097A
  07.
  08.SQL> select username,account_status from dba_users where username in(‘SYS‘,‘SCOTT‘);
  09.
  10.USERNAME                       ACCOUNT_STATUS
  11.------------------------------ --------------------------------
  12.SCOTT                          OPEN
  13.SYS                            OPEN
  SQL> select name,ASTATUS,password from user$ where name IN(‘SYS‘,‘SCOTT‘);
  NAME                              ASTATUS PASSWORD
  ------------------------------ ---------- ------------------------------
  SCOTT                                   0 E65E6AF62B2449CF
  SYS                                     0 8A8F025737A9097A
  SQL> select username,account_status from dba_users where username in(‘SYS‘,‘SCOTT‘);
  USERNAME                       ACCOUNT_STATUS
  ------------------------------ --------------------------------
  SCOTT                          OPEN
  SYS                            OPEN
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原文地址:http://www.cnblogs.com/furenjian/p/5068307.html