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Given a non-negative number represented as an array of digits, plus one to the number.
The digits are stored such that the most significant digit is at the head of the list.
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题目大意就是用一个int数组来模拟十进制数加１的计算，需要注意的地方就是溢出的情况．
1 public class Solution { 2 public int[] plusOne(int[] digits) { 3 int len = digits.length; 4 digits[len-1]++; 5 boolean flag = false;//是否溢出 6 for(int i=len -1; i>=0;i--){ 7 if(digits[i] >= 10) { 8 if(i != 0){ 9 digits[i-1]++; 10 }else{ 11 flag =true; 12 } 13 digits[i] -= 10; 14 } 15 } 16 if(flag == true){ 17 int[] res = new int[len+1]; 18 res[0] = 1; 19 for(int i = 0;i<len;i++){ 20 res[i+1] = digits[i]; 21 } 22 return res; 23 }else{ 24 return digits; 25 } 26 27 } 28 }
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原文地址：http://www.cnblogs.com/guoguolan/p/5455074.html
