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C#LINQ 查询【学习笔记】

时间:2016-10-25 02:27:01      阅读:254      评论:0      收藏:0      [点我收藏+]

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【LINQ 查询】
 
 2016-10-24

事例:
 
先定义两个类Master和KongFu,然后在这两个类中定义变量
  1.  1 class Master
     2 {
     3     publicintId{ get;set;}
     4     publicstringName{ get;set;}
     5     publicintAge{ get;set;}
     6     publicstringKongfu{ get;set;}
     7     publicstringMenPai{ get;set;}
     8     publicintLevel{ get;set;}
     9     public overide string ToString()
    10    {
    11         return string.Fromat("Id:{0},Name:{1},Age:{2},Kongfu:{3},MenPai:{4},Level:{5}", Id, Name, Age, Kongfu, Menpai, Leve)
    12    }
    13 }    
     1 class KongFu
     2 {
     3    public int Id { get;set;}
     4    public string Name { get;set;}
     5    public int Power { get;set;}
     6 
     7    public override string ToString()
     8    {
     9       return string.Format("Id:{0},Name:{1},Power:{2}", Id, Name, Power);
    10    }
    11 }

     

     1 static void Main(String[] args)
     2 {
     3     var master =newList<Master>()
     4     {
     5         newMaster(){Id=1,Name="黄蓉",Age=18,Menpai="丐帮", Kongfu="打狗棒法",Level=9},
     6         newMaster(){Id=2,Name="洪七公",Age=70,Menpai="丐帮", Kongfu="打狗棒法",Level=10},
     7         newMaster(){Id=3,Name="郭靖",Age=22,Menpai="丐帮", Kongfu="降龙十八掌",Level=10},
     8         newMaster(){Id=4,Name="任我行",Age=50,Menpai="明教", Kongfu="葵花宝典",Level=1},
     9         newMaster(){Id=5,Name="东方不败",Age=35,Menpai="明教", Kongfu="葵花宝典", Level=10},
    10         newMaster(){Id=6,Name="林平之",Age=23,Menpai="华山", Kongfu="葵花宝典", Level=7},
    11         newMaster(){Id=7,Name="岳不群", Age=50,Menpai="华山",Kongfu="葵花宝典",Level=8},
    12         newMaster(){Id=8,Name="令狐冲",Age=23,Menpai="华山",Kongfu="独孤九剑", Level=10},
    13         newMaster(){Id=9,Name="梅超风",Age=23,Menpai="梅花岛",Kongfu="九阴真经", Level=10},
    14         newMaster(){Id=10,Name="黄药师",Age=23,Menpai="梅花岛",Kongfu="弹指神功",Level=10},
    15         newMaster(){ Id = 11, Name = "风清扬", Age = 23, Menpai = "华山", Kongfu = "独孤九剑", Level = 10 }
    16     };
    17     var kongfu =newList<KongFu>()
    18     {
    19         newKongFu(){Id=1,Name="打狗棒法", Power=95 },
    20         newKongFu(){Id=2,Name="降龙十八掌",Power=100},
    21         newKongFu(){Id=3,Name="葵花宝典", Power=100},
    22         newKongFu(){Id=4,Name="独孤九剑", Power=100},
    23         newKongFu(){Id=5,Name="九阴真经", Power=100},
    24         newKongFu(){Id=6,Name="弹指神功", Power=100},
    25     };
    26 }            

开始建立查询:

【第一种】:找出Level大于8的列表来
         var result = new List<Master>();
            foreach (var item in master)
            {
                if (item.Level > 8)
                {
                    result.Add(item);
                }
            }
            foreach (var item in result)
            {
                Console.WriteLine(item.ToString());//ToString()不写默认存在
            }
            Console.ReadKey();
          //需要在 master类和KongFu中创建 ToString()方法,因为在查询完以后进行遍历(foreach)的时候h会出现以下错误

【第二种】:利用专业查询语言查找并排序
    //from:表示从哪个集合里查找……where:查新条件……select:返回结果列表
            var result2 = from m in master
                          where m.Level < 10//查询条件
                          orderby m.Level//根据level进行升序排序
                          orderby m.Level descending//根据level进行降序排序
                          select m;
            foreach (var item in result2)
            {
                Console.WriteLine(item);
            }
            Console.ReadKey();
 
  【按条件查找并排序】

            var ressult22 = from m in master.Where(m => m.Level < 10).OrderBy(m => m.Age)//OrderBy && OrderByDescending   升序和降序 排列
                            select m;
            foreach (var item in ressult22)
            {
                Console.WriteLine(item);
            }
            Console.ReadKey();

 
【第三种】:调用函数的方法来实现查找功能
        var result3 = master.Where(T1);
            foreach (var item in result3)
            {
                Console.WriteLine(item);
            }
            Console.ReadKey();
       //需要调用的类
        static bool T1(Master m)
        {
            if (m.Level < 10)
            { return true; }
            else
            { return false; }
        }


【第四种】:利用lamada表达式查找
        var result4 = master.Where(m => m.Level < 10);//lamada表达式    参数名=>表达式
            foreach (var item in result4)
            {
                Console.WriteLine(item);
            }
            Console.ReadKey();

【第五种】:将两个列表联合起来,形成 Count(master) * Count(Kongfu) 的列表
        var result5 = from m in master
                          from f in kongfu
                          select new { mm = m, ff = f };//
            foreach (var item in result5)
            {
                Console.WriteLine(item);
            }
            Console.ReadKey()
【第六种】:查询当 master.Level
== Kongfu.Id,时两个的信息 var result6 = from m in master from f in kongfu //where m.Level == f.Id where m.Kongfu == f.Name && f.Power > 90 select new { mm = m, ff = f }; foreach (var item in result6) { Console.WriteLine(item); } Console.ReadKey();
【第七种】:实现master和Kongfu中属性相等的信息输出
var result7 = from m in master //将kongfu列表中的信息放入k中,选出 m.Kongfu == k.Name的信息 join k in kongfu on m.Kongfu equals k.Name select new { mm = m, kk = k }; foreach (var item in result7) { Console.WriteLine(item); } Console.ReadKey(); 【第八种】:一人修炼一门功夫,一门功夫被多少人修炼 var result8 = from k in kongfu join m in master on k.Name equals m.Kongfu into groups//把武林高手分类,看看哪门功夫被人修炼的多 orderby groups.Count()//按照修炼人进行 select new { kongfu = k, count = groups.Count() };//groups.count:获取到 foreach (var item in result8) { Console.WriteLine(item); } Console.ReadKey();

//将修炼功夫一样的人放在一起并输出master和kongfu的信息
var result = from k in kongfu join m in master on k.Name equals m.Kongfu select new { mm = m, kk = k }; foreach (var item in result) { Console.WriteLine(item); } Console.ReadKey();
【第九种】:按照自身帮派进行分组,
var result9 = from m in master group m by m.Menpai//将门派分组,放到m中 into p//表示放到p中 select new { count = p.Count(), key = p.Key };//count = p.Count()表示这组有多少人 //key = p.Key表示这个是按照什么分的,即关键字"Key"为Menpai foreach (var item in result9) { Console.WriteLine(item); } Console.ReadKey(); 【第十种】:确定序列中元素是否满足条件 Any在内部循环遍历每个元素 根据m=>m.Menpai判断是否满足条件 bool result10 = master.Any(m => m.Menpai == "丐帮"); Console.WriteLine(result10); Console.ReadKey();
 
 



C#LINQ 查询【学习笔记】

标签:equals   int   height   利用   需要   1.3   color   相等   列表   

原文地址:http://www.cnblogs.com/awen001/p/5995046.html

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