之前看到了这道shell面试题:获取51CTO博客列表按时间倒序排序http://oldboy.blog.51cto.com/2561410/1860985
由于学了一段时间的python,试想着能否使用python来解题
思路:通过requests模块获取网页源码,通过split()函数获取总页数,拼接字符串获取所有博客地址的url。同样,通过requests获取所有页面的源码并通过正则匹配,获取关键信息,从而拼接出html页面。
#coding:utf-8
import requests
import re,sys
reload(sys)
sys.setdefaultencoding(‘utf-8‘)
# 获取页数
def page():
url = ‘http://oldboy.blog.51cto.com/all/2561410‘
content = requests.get(url).content
msg = re.findall(r‘<center>(.*)</center>‘,content)[0]
return msg.split(‘/‘)[-1].split()[0]
# 获取关键信息并拼接html
def oldboy():
uri = ‘http://oldboy.blog.51cto.com/all/2561410/page/‘
num = page()
res = []
for i in range(int(num)):
url = uri + str(int(i)+1)
content = requests.get(url).content
res += re.findall(r‘<a href="(/\d+/\d+)">(.*)</a>‘,content)
# res格式[(‘/2561410/1867160‘,‘2017\xd7\xee\xd0\xc2\xc6\xf3\xd2\xb5Shell\xc3\xe6\xca\xd4\xcc\xe2\xbc\xb0\xc6\xf3\xd2\xb5\xd4\xcb\xce\xac\xca\xb5\xd5\xbd\xb9\xb230\xb5\xc0\xb0\xb8\xc0\xfd‘),...]
html = ‘‘
for i in res:
msg = i[1].decode(‘gbk‘)
href = ‘http://oldboy.blog.51cto.com‘+i[0]
html += "<p><br></p><p>{0}</p><p><a href=‘{1}‘ target=‘_blank‘>{1}</a></p>".format(msg,href)
# html格式"<p><br></p><p>2017最新企业Shell面试题及企业运维实战共30道案例</p><p><a href=‘http://oldboy.blog.51cto.com/2561410/1867160‘ target=‘_blank‘>http://oldboy.blog.51cto.com/2561410/1867160</a></p>..."
with open(‘oldboy_blog.html‘,‘w‘) as f:
f.write(html)
if __name__==‘__main__‘:
oldboy()html页面
原文地址:http://yaoliang83.blog.51cto.com/10991353/1869296