ajax控制页面跳转

<form>
    <table style="margin: 200px auto;">
        <tr>
            <td><label for="login_userName">用户名</label></td>
            <td><input type="text" class="form-control" id="login_userName" placeholder="用户名">
            </td>
        </tr>
        <tr>
            <td><label for="login_password">密 码</label></td>
            <td><input type="password" class="form-control" id="login_password" placeholder="密 码">
            </td>
        </tr>
        <tr>
            <td><button type="submit" class="btn btn-default" onclick="login()">登录</button></td>
        </tr>
    </table>
</form>

function login(){
    var loginInfo = {
        "loginname":$("#login_userName").val().trim(),
        "password":$("#login_password").val().trim()
    }
    var timestamp=new Date().getTime();
    var url="/pub/frame.html?timestamp="+timestamp;
    $.ajax({
        url: ‘/login/login.do‘,
        type: ‘post‘,
        dataType: ‘json‘,
        contentType:‘application/json‘,
        async:false,
        data: JSON.stringify(loginInfo),
        success: function (data) {
            //正常回调
            if(data.status==0){
                $("#login_userName").val("");
                $("#login_password").val("");
                window.location.href=url;
            }else if(data.status==1) {
                alert(data.msg);
            }
        },
        error:function (data) {
            alert(data.msg);
        }
    });
}