码迷,mamicode.com
首页 > 编程语言 > 详细

leetcode 223. Rectangle Area 计算面积---------- java

时间:2017-05-24 18:27:07      阅读:224      评论:0      收藏:0      [点我收藏+]

标签:style   top   http   val   else   fine   span   计算   border   

Find the total area covered by two rectilinear rectangles in a 2D plane.

Each rectangle is defined by its bottom left corner and top right corner as shown in the figure.

技术分享

Assume that the total area is never beyond the maximum possible value of int.

 

 

计算图形面积;

 

 

两个矩形面积减去重复的面积即可。

public class Solution {
    public int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
        
        int area = (C - A) * (D - B) + (G - E) * (H - F);
        
        if (B > H || F > D || A > G || C < E)
            return area;
        int x1 = Math.max(A, E);
        int y1 = Math.max(B, F);
        int x2 = Math.min(C, G);
        int y2 = Math.min(D, H);
        int result = (x2 - x1) * (y2 - y1);
        if (result > 0){
            return area - result;
        } else {
            return area + result;
        }
    }
}

 

 

 

leetcode 223. Rectangle Area 计算面积---------- java

标签:style   top   http   val   else   fine   span   计算   border   

原文地址:http://www.cnblogs.com/xiaoba1203/p/6900195.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!