笨办法学Python（三十一）

时间：2017-09-06 23:54:43 阅读：268 评论：0 收藏：0 [点我收藏+]

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习题 31: 作出决定

这本书的上半部分你打印了一些东西，而且调用了函数，不过一切都是直线式进行的。你的脚本从最上面一行开始，一路运行到结束，但其中并没有决定程序流向的分支点。现在你已经学了 if, else, 和 elif ，你就可以开始创建包含条件判断的脚本了。

上一个脚本中你写了一系列的简单提问测试。这节的脚本中，你将需要向用户提问，依据用户的答案来做出决定。把脚本写下来，多多鼓捣一阵子，看看它的工作原理是什么。

 1 print "You enter a dark room with two doors.  Do you go through door #1 or door #2?"
 2 
 3 door = raw_input("> ")
 4 
 5 if door == "1":
 6     print "There‘s a giant bear here eating a cheese cake.  What do you do?"
 7     print "1. Take the cake."
 8     print "2. Scream at the bear."
 9 
10     bear = raw_input("> ")
11 
12     if bear == "1":
13         print "The bear eats your face off.  Good job!"
14     elif bear == "2":
15         print "The bear eats your legs off.  Good job!"
16     else:
17         print "Well, doing %s is probably better.  Bear runs away." % bear
18 
19 elif door == "2":
20     print "You stare into the endless abyss at Cthulhu‘s retina." 
21     print "1. Blueberries."
22     print "2. Yellow jacket clothespins."
23     print "3. Understanding revolvers yelling melodies."
24 
25     insanity = raw_input("> ")
26 
27     if insanity == "1" or insanity == "2":
28         print "Your body survives powered by a mind of jello.  Good job!"
29     else:
30         print "The insanity rots your eyes into a pool of muck.  Good job!"
31 
32 else:
33     print "You stumble around and fall on a knife and die.  Good job!"