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最大堆(Java数组实现)

时间:2017-12-02 19:12:34      阅读:243      评论:0      收藏:0      [点我收藏+]

标签:左右   ati   cap   mic   getc   font   div   i++   swap   

最大堆

data[1]开始存,data[0]空着不用。也可以把data[0]当成size来用。

 

public class MaxHeap<T extends Comparable<? super T>> {
    protected T[] data;
    protected int size;
    protected int capacity;

    public MaxHeap(int capacity) {
        this.data = (T[]) new Comparable[capacity + 1];
        size = 0;
        this.capacity = capacity;
    }

    public int size() {
        return this.size;
    }

    public boolean isEmpty() {
        return size == 0;
    }

    public int getCapacity() {
        return this.capacity;
    }

    /**
     * @return 查看最大根(只看不删, 与popMax对比)
     */
    public T seekMax() {
        return data[1];
    }

    public void swap(int i, int j) {
        if (i != j) {
            T temp = data[i];
            data[i] = data[j];
            data[j] = temp;
        }
    }

    public void insert(T item) {
        size++;
        data[size] = item;
        shiftUp(size);
    }

    /**
     * @return 弹出最大根(弹出意味着删除, 与seekMax对比)
     */
    public T popMax() {
        swap(1, size--);
        shiftDown(1);
        return data[size + 1];
    }

    /**
     * @param child 孩子节点下角标是child,父节点下角表是child/2
     */
    public void shiftUp(int child) {
        while (child > 1 && data[child].compareTo(data[child / 2]) > 0) {
            swap(child, child / 2);
            child = child / 2;
        }
    }

    /**
     * @param a data数组中某个元素的下角标
     * @param b data数组中某个元素的下角标
     * @return 哪个元素大就返回哪个的下角标
     */
    private int max(int a, int b) {
        if (data[a].compareTo(data[b]) < 0) {//如果data[b]大
            return b;//返回b
        } else {//如果data[a]大
            return a;//返回a
        }
    }

    /**
     * @param a data数组中某个元素的下角标
     * @param b data数组中某个元素的下角标
     * @param c data数组中某个元素的下角标
     * @return 哪个元素大就返回哪个的下角标
     */
    private int max(int a, int b, int c) {
        int biggest = max(a, b);
        biggest = max(biggest, c);
        return biggest;
    }


    /**
     * @param father 父节点下角标是father,左右两个孩子节点的下角表分别是:father*2 和 father*2+1
     */
    public void shiftDown(int father) {
        while (true) {
            int lchild = father * 2;//左孩子
            int rchild = father * 2 + 1;//右孩子
            int newFather = father;//newFather即将更新,父、左、右三个结点谁大,newFather就是谁的下角标

            if (lchild > size) {//如果该father结点既没有左孩子,也没有右孩子
                return;
            } else if (rchild > size) {//如果该father结点只有左孩子,没有右孩子
                newFather = max(father, lchild);
            } else {//如果该father结点既有左孩子,又有右孩子
                newFather = max(father, lchild, rchild);
            }

            if (newFather == father) {//说明father比两个子结点都要大,表名已经是大根堆,不用继续调整了
                return;
            } else {//否则,还需要继续调整堆,直到满足大根堆条件为止
                swap(father, newFather);//值进行交换
                father = newFather;//更新father的值,相当于继续调整shiftDown(newFather)
            }
        }
    }

    public static void main(String[] args) {
        //创建大根堆
        MaxHeap<Integer> maxHeap = new MaxHeap<Integer>(100);
        //向堆里存
        for (int i = 0; i < 100; i++) {
            maxHeap.insert((int) (Math.random() * 100));
        }

        //创建数组
        Integer[] arr = new Integer[100];
        //从堆里取,放进数组里
        for (int i = 0; i < 100; i++) {
            arr[i] = maxHeap.popMax();
            System.out.print(arr[i] + " ");
        }
        System.out.println();
    }
} 

 最大堆:shiftDown()函数与上面不一样

public class MaxHeap<T extends Comparable<? super T>> {
    protected T[] data;
    protected int size;
    protected int capacity;

    public MaxHeap(int capacity) {
        data = (T[]) new Comparable[capacity + 1];
        this.capacity = capacity;
        size = 0;
    }

    public int size() {
        return size;
    }

    public boolean isEmpty() {
        return size == 0;
    }

    public void insert(T item) {
        data[size + 1] = item;
        size++;
        shiftUp(size);
    }

    /**
     * @return 弹出最大根(弹出意味着删除, 与seekMax对比)
     */
    public T popMax() {
        T ret = data[1];
        swap(1, size);
        size--;
        shiftDown(1);
        return ret;
    }

    /**
     * @return 查看最大根(只看不删, 与popMax对比)
     */
    public T seekMax() {
        return data[1];
    }

    public void swap(int i, int j) {
        if (i != j) {
            T temp = data[i];
            data[i] = data[j];
            data[j] = temp;
        }
    }

    public void shiftUp(int k) {
        while (k > 1 && data[k / 2].compareTo(data[k]) < 0) {
            swap(k, k / 2);
            k /= 2;
        }
    }

    public void shiftDown(int father) {
        while (2 * father <= size) {
            int newFather = 2 * father;
            if (newFather + 1 <= size && data[newFather + 1].compareTo(data[newFather]) > 0) {//data[j] data[j+1]两者取大的那个
                newFather = newFather + 1;
            }
            if (data[father].compareTo(data[newFather]) >= 0) {
                break;
            } else {
                swap(father, newFather);//值进行交换
                father = newFather;//newFather是(2*father)或者是(2*father+1),也就是继续shiftDown(newFather);
            }
        }
    }

    public static void main(String[] args) {
        //创建大根堆
        MaxHeap<Integer> maxHeap = new MaxHeap<Integer>(100);
        //向堆里存
        for (int i = 0; i < 100; i++) {
            maxHeap.insert((int) (Math.random() * 100));
        }

        //创建数组
        Integer[] arr = new Integer[100];
        //从堆里取,放进数组里
        for (int i = 0; i < 100; i++) {
            arr[i] = maxHeap.popMax();
            System.out.print(arr[i] + " ");
        }
        System.out.println();
    }
}

  

最大堆(Java数组实现)

标签:左右   ati   cap   mic   getc   font   div   i++   swap   

原文地址:http://www.cnblogs.com/noKing/p/7954898.html

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