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【转载】C++高精度运算类bign (重载操作符)

时间:2017-12-15 20:50:17      阅读:160      评论:0      收藏:0      [点我收藏+]

标签:++   amp   return   else   clean   iostream   namespace   false   opera   

#include<cstdio>  
#include<cstring>   
#include<iostream>  
using namespace std;  
  
const int maxn = 200;  
struct bign{  
  int len, s[maxn];  
    
  /*以下的构造函数是C++中特有的,作用是进行初始化。 
   事实上,当定义bign x时,就会执行这个函数,把x.s清零,并赋x.len=1 。 
   需要说明的是,在C++中,并不需要typedef就可以直接用结构体名来定义,而且 
   还提供“自动初始化”的功能,从这个意义上说,C++比C语言方便   
  */   
  bign() {  
    memset(s, 0, sizeof(s));  
    len = 1;  
  }  
  
  bign(int num) {  
    *this = num;  
  }  
  
  //定义为const参数,作用是 不能对const参数的值做修改   
  bign(const char* num) {  
    *this = num;  
  }  
  /*以上是构造方法,初始化时对执行相应的方法*/  
  
  bign operator = (int num) {  
    char s[maxn];  
    sprintf(s, "%d", num);  
    *this = s;  
    return *this;  
  }   
  
  //函数定义后的const关键字,它表明“x.str()不会改变x”   
  string str() const {  
    string res = "";  
    for(int i = 0; i < len; i++) res = (char)(s[i] + ‘0‘) + res;  
    if(res == "") res = "0";  
    return res;  
  }  
    
  void clean() {  
    while(len > 1 && !s[len-1]) len--;  
  }  
    
    
  /* 以下是重载操作符 */   
  bign operator = (const char* num) {  
    //逆序存储,方便计算   
    len = strlen(num);  
    for(int i = 0; i < len; i++) s[i] = num[len-i-1] - ‘0‘;  
    return *this;  
  }  
    
  bign operator + (const bign& b) const{  
    bign c;  
    c.len = 0;  
    for(int i = 0, g = 0; g || i < max(len, b.len); i++) {  
      int x = g;  
      if(i < len) x += s[i];  
      if(i < b.len) x += b.s[i];  
      c.s[c.len++] = x % 10;  
      g = x / 10;  
    }  
    return c;  
  }  
  
  bign operator * (const bign& b) {  
    bign c; c.len = len + b.len;  
    for(int i = 0; i < len; i++)  
      for(int j = 0; j < b.len; j++)  
        c.s[i+j] += s[i] * b.s[j];  
    for(int i = 0; i < c.len-1; i++){  
      c.s[i+1] += c.s[i] / 10;  
      c.s[i] %= 10;  
    }  
    c.clean();  
    return c;  
  }  
  
  bign operator - (const bign& b) {  
    bign c; c.len = 0;  
    for(int i = 0, g = 0; i < len; i++) {  
      int x = s[i] - g;  
      if(i < b.len) x -= b.s[i];  
      if(x >= 0) g = 0;  
      else {  
        g = 1;  
        x += 10;  
      }  
      c.s[c.len++] = x;  
    }  
    c.clean();  
    return c;  
  }  
  
  bool operator < (const bign& b) const{  
    if(len != b.len) return len < b.len;  
    for(int i = len-1; i >= 0; i--)  
      if(s[i] != b.s[i]) return s[i] < b.s[i];  
    return false;  
  }  
  
  bool operator > (const bign& b) const{  
    return b < *this;  
  }  
  
  bool operator <= (const bign& b) {  
    return !(b > *this);  
  }  
  
  bool operator == (const bign& b) {  
    return !(b < *this) && !(*this < b);  
  }  
  
  bign operator += (const bign& b) {  
    *this = *this + b;  
    return *this;  
  }  
};  
  
istream& operator >> (istream &in, bign& x) {  
  string s;  
  in >> s;  
  x = s.c_str();  
  return in;  
}  
  
ostream& operator << (ostream &out, const bign& x) {  
  out << x.str();  
  return out;  
}  
  
int main() {  
  bign a;  
  cin >> a;  
  a += "123456789123456789000000000";  
  cout << a*2 << endl;  
  return 0;  
}  

  

【转载】C++高精度运算类bign (重载操作符)

标签:++   amp   return   else   clean   iostream   namespace   false   opera   

原文地址:http://www.cnblogs.com/YMY666/p/8044693.html

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