C语言实现''student a am i''字符串的正确排列

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#include<stdlib.h>

int Reverse(char a[],char b[],int len)
{
    int i = 0;
    
    //建立一个新数组用来储存逆序的语言
    for (int i = 0; i <= len; i++)
    {
        if (a[i] == ‘\0‘)
        {
            return 0;
        }
        b[len-i-2] = a[i];
    }

    return 0;
}

int ArrangeWords(char a[],char b[], int len)
{
    /*先判断是否多过一个字符     *
     * 再将多个字符的位置全部交换*/
    int left = 0;
    int right = 0;
    int j = 0;
    for (int i = 0; i < len-1; i++)                                   
    {
        if (b[i] == ‘ ‘)                                            
        {
            left = i + 1;
            a[i] = b[i];
            continue;
        }
        
        if (b[i] != ‘ ‘)
        {
            if ((b[i + 1] == ‘ ‘)||(i+2==len))
            {
                right = i;
                for ( j = left; j <= right; j++)                //交换字符
                {
                    a[j] = b[left+right-j];                               
                    continue;
                }

            }
            continue;
        }    

        if (b[i] == ‘\n‘)
        {
            break;
        }
    
    }

    return 0;
}

int main(){
    char a[] = "student a am i";
    char b[] = "student a am i";
    
    
    int len = sizeof(a) / sizeof(a[0]);
    for (int i = 0; i < len; i++)
    {
        printf("%c", a[i]);
    }
    printf("\n");
    
    
    //逆序
    Reverse(a,b, len);
    //排列单词
    ArrangeWords(a,b, len);


    for (int i = 0; i < len; i++)
    {
        printf("%c", b[i]);
    }
    printf("\n");


    for (int i = 0; i < len; i++)
    {
        printf("%c", a[i]);
    }
    printf("\n");


    system("pause");
    return 0;
}