码迷,mamicode.com
首页 > 编程语言 > 详细

python习题20190130

时间:2019-01-30 18:27:27      阅读:212      评论:0      收藏:0      [点我收藏+]

标签:ping   嵌套循环   包括   jin   支付   cheng   ==   计算   输入数据   

#encoding=utf-8

‘‘‘
一家商场在降价促销。如果购买金额50-100元(包含50元和100元)之间,会给10%的折扣,如果购买金额大于100元会给20%折扣。编写一程序,询问购买价格,再显示出折扣(10%或20%)和最终价格
‘‘‘

def print_zekou():
    aount = int(input("请输入你购买的金额:"))
    if aount < 50:
        print("不好意思你购买的金额没有折扣,需要支付的金额为:",aount)

    if aount >= 50 and aount <= 100:
        print("你购买的金额为 %d,折扣为:%d,需要支付的金额为%0.2f"%(aount,9,aount*0.9))
    if aount > 100:
        print("你购买的金额为 %d,折扣为:%d,需要支付的金额为%0.2f"%(aount,8,aount*0.8))

‘‘‘
10、求1 + 2 + 3 +….+100
‘‘‘
def print_num_yibai():
    num = 0
    for i in range(1,101):
        num += i
    print("1 + 2 + 3 +….+100=",num)

‘‘‘
判断一个数n能否同时被3和5整除
‘‘‘
def print_n_sanhuowu():
    num = int(input())
    if num ==0:
        return 0
    if num % 3==0 and num %5 ==0:
        print("能被3和5整除")
    else:
        return 0

‘‘‘
一个足球队在寻找年龄在10到12岁的小女孩(包括10岁和12岁)加入。编写一个程序,询问用户的性别(m表示男性, f表示女性)和年龄,然后显示一条消息指出这个人是否可以加入球队,询问10次后,输出满足条件的总人数
‘‘‘
def print_f():
    count = 0
    for i in range(10):
        num = input("m表示为男性,f表示为女性:")
        if num == f:
            sunm = int(input("请输入年龄:"))
            if sunm >=10 and sunm <= 12:
                print("恭喜你可以加入球队!!")
                count += 1

        else:
            print("不好意思,我们不需要男生!!")
    print("加入球队的总人数为:",count)

‘‘‘
长途旅行中,刚到一个加油站,距下一个加油站还有200km,而且以后每个加油站之间距离都是200km。编写一个程序确定是不是需要在这里加油,还是可以等到接下来的第几个加油站再加油
‘‘‘
def print_km():
    youxiang = int(input("你的油箱多大?,单位升:"))
    shxia = float(input("目前你的油箱还有多少油,按百分比,比如一半就是0.5:"))
    lucheng = int(input("你的车每升油能走多远:"))
    syou = (youxiang*shxia-5)*lucheng
    if syou < 200:
        print("在当前的加油站要加油")
    else:
        print("第%d个加油站加油"%(syou/200))

#20190118
‘‘‘
现有面包、热狗、番茄酱、芥末酱以及洋葱,数字显示有多少种订购组合,其中面包必订,0不订,1订,比如10000,表示只订购面包
‘‘‘
def print_ding():
    count = 0
    for a in 1:
        for b in 01:
            for c in 01:    
                for d in 01:
                    print(a+b+c+d)
                    count += 1
    print("有%d种组合"%count)
    
‘‘‘
基于上题:给出每种食物的卡路里(自定义),再计算出每种组合总共的卡路里
‘‘‘
def print_ding_kaluli():
    count = 0
    for a in 1:
        for b in 01:
            for c in 01:    
                for d in 01:
                    print(a+b+c+d,"不同组合的卡路里为",int(a)*100+int(b)*200+int(c)*300+int(d)*400)
                    count += 1

‘‘‘
输入5个名字,排序后输出
‘‘‘
def print_fivename_sorted():
    num = input("请输入5个名字,用英文都好隔开:")
    num_list = num.split(,)
    print(sorted(num_list))

‘‘‘
实现一个简单的单词本
- 功能:
- 可以添加单词和词义,当所添加的单词已存在,让用户知道;
- 可以查找单词,当查找的单词不存在时,让用户知道;
- 可以删除单词,当删除的单词不存在时,让用户知道;
- 以上功能可以无限制操作,直到用户输入bye退出程序。

‘‘‘
def print_smiple_danciben():
    num_dict = {}
    while True:
        num = input("请输入你要进行的操作(add:添加单词,select:查找单词,del:删除单词,bye:退出程序):")
        if num ==bye:
            break
        if num == add:
            num_add = input("输入你要添加的单词:")
            if num_add in num_dict.keys():
                print("你输入的单词已存在!!")
                continue
            else:
                num_value = input("输入你添加的单词的词义:")
            num_dict[num_add] = num_value
            
        if num == select:
            num_select = input("输入你要查找的单词:")
            if num_select not in num_dict.keys():
                print("你要查询的单词不存在!!")
            else:
                print(num_select," 单词词义为:",num_dict[num_select])
        if num == del:
            num_del = input("输入你要删除的单词:")
if num_del not in num_dict.keys(): print("你要删除的单词不存在!!") else: del num_dict[num_del] print("已删除成功") if num == bye: print("程序已结束,感谢你的使用") break if num !=add and num !=del and num != select and num != bye: print("输入有误,请输入正确的操作符!!") continue ‘‘‘ 输入一个正整数,输出其阶乘结果 ‘‘‘ def print_jiecheng(n): num = 1 if not isinstance(n,int): return "输入的不是数值!!" if n == 0: return 1 for i in range(1,n+1): num *= i print(n,"的阶乘为:",num) ‘‘‘ 输入3个数字,以逗号隔开,输出其中最大的数 ‘‘‘ def print_three_num(): num = input("请输入三个数值并用英文逗号隔开:") num_list = num.split(",") num_son = int(num_list[0]) for i in num_list: if num_son < int(i): num_son = int(i) print("最大的数为:",num_son) ‘‘‘ 输入一个年份,输出是否为闰年 是闰年的条件: 能被4整数但不能被100整除,或者能被400整除的年份都是闰年 ‘‘‘ def print_runnian(): num_year = int(input("请输入你要判断的年份:")) if (num_year %4 ==0 and num_year %100 !=0) or num_year%400 == 0: print(num_year,"是闰年!") else: print(num_year,"不是闰年!") #20190121 ‘‘‘ 求两个正整数m和n的最大公约数 ‘‘‘ def print_max(n,m): num_list=[] if n%m == 0: return m if m%n == 0: return n for i in range(1,n+1): if n%i == 0 and m%i ==0: num_list.append(i) for i in range(1,m+1): if n%i == 0 and m%i ==0: num_list.append(i) return max(num_list) ‘‘‘ 习题1:设定一个用户名和密码,用户输入正确的用户名和密码,则显示登录成功,否则提示登录失败,用户最多失败3次,否则退出程序。 提示:使用while或者for来限定重试的次数,使用input获取用户输入使用 ==判断用户的用户名和密码。 ‘‘‘ def print_username_passs(): num_one = 0 num_two = 3 while num_one < 3: num_username = input("请输入用户名:") num_passwed = input("请输入用户密码:") if num_username == testname and num_passwed == testpass: return "登录成功" else: print("登录失败!!") num_two -= 1 print("剩下%d次机会"%num_two) num_one += 1 print("三次机会已经全部用完!!") return ‘‘ ‘‘‘ 习题2:自己实现一个函数,在一句话中查找某个单词的算法,存在返回索引号,否则返回False 提示:使用句子中的坐标遍历句子的每一个位置,使用查找单词的长度结合使用切片来查找单词。例如:s[i:i+len(单词)] ‘‘‘ def print_find_word(word,num): for i in range(len(word)): #print(i) #print(word[i:len(num)+i]) if len(word[i:]) <= len(num): print("没有找到!!") return 0 elif word[i:len(num)+i] == num: #print(word[i:len(num)-1]) print("索引:",i+1) return 1 ‘‘‘ 习题3:随机生成一个整数,1-100之间你最多猜5次,如果猜大了,提示大了小了,提示小了,猜对了,提示猜中。5次都没猜中,就猜没猜中。 ‘‘‘ import random def print_random_cai(): try: num_random = random.randint(1,100) print(num_random ) for i in range(5): num_one = int(input("请输入你要猜的数值:")) if num_one > num_random: print("猜大了!!") continue if num_one == num_random: print("猜中了!!") return 1 if num_one < num_random: print("猜小了!!") continue print("没猜中!!") except Exception as e: print(e) ‘‘‘ 习题4:使用while,计算随机数之和,超过100的时候,停止程序。随机数1-20的范围产生,要求记录一下产生的随机数,以及最后的和,以及随机数的个数。 ‘‘‘ def print_random_yibai(): num_one = 0 num_list = [] while num_one < 100: num_random = random.randint(1,20) num_list.append(num_random) num_one += num_random print("产生的随机数为:",num_list,"最后的和为:",num_one,"随机数的个数为:",len(num_list)) ‘‘‘ 习题5:遍历字符串、列表,分别基于位置和和基于字符遍历 ‘‘‘ def print_str_list(s): for i in s: print(i) for i in range(len(s)): print(s[i]) #20190122 ‘‘‘ 习题6:遍历一个列表中的嵌套列表和元组的所有元素,将1-12的数字进行输出![[[1,2,3],4,5],7,8,(9,10,(11,12))] ‘‘‘ def print_list_tuple(): num_tuple = [[[1,2,3],4,5],7,8,(9,10,(11,12))] for i in num_tuple: if isinstance(i,(list,tuple)): for j in i: if isinstance(j,(list,tuple)): for c in j: print(c) else: print(j) else: print(i) ‘‘‘ 判断一个数是否是素数 ‘‘‘ def print_sushu(n): if n == 1 or n == 2: print("是素数") return 0 for i in range(2,n): if n%i == 0: print("不是素数") return 1 else: print("是素数") return 0 ‘‘‘ 求100以内的素数和 ‘‘‘ def print_yibai_sushu(): num_one = 0 for i in range(3,101): num_two = print_sushu(i) print(i) if num_two == 0: num_one += i return num_one ‘‘‘ 使用 for 的方式,求一下100以内奇数之和 ‘‘‘ def print_for_jishu(): num_one = 0 for i in range(1,101,2): num_one += i print(num_one) ‘‘‘ 用户输入多个数字,当输入偶数的时候求和,输入奇数,不求和,输入.(一个点)的时候结束求和,打印求和结果 ‘‘‘ def print_oushu_qiuhe(): try: num_two = 0 while True: num_one = input("输入数值,偶数求和,奇数不求和,\".\"结束求和:") if num_one == .: print(num_two) break elif int(num_one)%2 == 0: num_two += int(num_one) except Exception as e: print(e) ‘‘‘ 嵌套循环输出10-50中个位带有1-5的所有数字: 方法1:数字和10取余,判断是否大于0并且小于等于5 方法2:将数字转换为str,取各位的字符判断字符是否在1-5内。 方法3:拼接数字 ‘‘‘ def print_shidegewei(): try: num_list = [] for i in range(10,51): if i%10 >0 and i%10 <= 5: print(i) num_list.append(i) return num_list except Exception as e: print(e) ‘‘‘ 输入3个数字,达到3个数字求和,结束程序 ‘‘‘ def print_three_num(): try: num_one = 0 for i in range(3): num = int(input("请输入数值")) num_one += num return num_one except Excepyion as e: print(e) ‘‘‘ 用户输入不同的数据,当输入的数据达到3个数字的时候,求和结束程序。(数字可以是整数) 提示:判断是否整数的方法,isdigit() 遍历所有的输入数据,判断是否在0-9的字符串范围内 ‘‘‘ def print_three_number(): try: counts = 0 num_one = 0 while True: num = input("请输入:") if num.isdigit(): counts += 1 num_one += int(num) if counts == 3: return num_one except Exception as e: print(e) ‘‘‘ 用嵌套列表的方式,遍历输出一个矩阵 ‘‘‘ def print_qiantao(): num_list = [[1,2,3],[4,5,6],[7,8,9]] for i in num_list: for j in i: print(j) ‘‘‘ ‘‘‘ def print_list_num(): try: num_list = [[1,2,3],[4,5,6],[7,8,9]] num_one = 0 num_two = 0 for i in range(len(num_list)): for j in range(len(num_list[i])): if i == j: num_one += num_list[i][j] num = len(num_list[i])-1-i num_two += num_list[i][num] print("正对角之和:",num_one,"反对角之和:",num_two,) except Exception as e: print(e) ‘‘‘ 求以下矩阵四边元素之和 l = [ [1,2,3,4,5], [1,2,3,4,5], [1,2,3,4,5], [1,2,3,4,5], [1,2,3,4,5] ] ‘‘‘ def print_sibinayuanshuzhihe(): num_list = [[1,2,3,4,5], [1,2,3,4,5], [1,2,3,4,5], [1,2,3,4,5], [1,2,3,4,5] ] num_one = 0 for i in range(len(num_list)): if i == 0 or i == len(num_list)-1: for j in num_list[i]: num_one += j else: num_one += num_list[i][0] + num_list[i][len(num_list)-1] continue print(num_one) ‘‘‘ 统计单词中包含字母a的单词个数 ‘‘‘ def print_danci_geshu(n): num = 0 num_one = n.split() for i in num_one: if a in i: num += 1 print(num) ‘‘‘ 成绩等级判断 利用条件运算符的嵌套来完成此题:学习成绩>=90分的同学用A表示, 60-89分之间的用B表示,60分以下的用C表示 ‘‘‘ def print_student_score(n): if n >= 90: print("A") if n >= 60 and n < 90: print("B") if n < 60: print("C") #20190125 ‘‘‘ 实现数学中多项式求和公式的打印 比如:a6x^6 + a5x^5 + a4x^4 + a3x^3 + a2x^2 + a1x^1 + a0 ‘‘‘ def print_duoxiangshi(n): num_str = ‘‘ num_list = range(0,n+1) for i in num_list[::-1]: if i ==0: num_str += a+str(i) else: num_str += a+str(i)+x+^+str(i)++ print(num_str) ‘‘‘ 统计名字列表中,各名字的首字母在名字列表中出现的次数 ‘‘‘ def print_shouzimu(): names = ["huhongqiang","zhangsan","lisi","wangwu","wuda","ziliao"] num_dict = {} for i in names: if i[0] in num_dict.keys(): num_dict[i[0]] += 1 else: num_dict[i[0]] = 1 print(num_dict) ‘‘‘ 输入三个数,判断是否能构成三角形 能构成三角形三边关系: 三边都大于零 两边之和大于第三边,两边之差小于第三边 ‘‘‘ def print_sanjiao(): num_one = int(input("请输入第一边:")) num_two = int(input("请输入第二边:")) num_three = int(input("请输入第三边:")) if num_one ==0 or num_two ==0 or num_two == 0: return "有一边为0,不是三角形!!" if not (num_one+num_two >num_three and num_one+num_three >num_two and num_two + num_three >num_one): return "任意两边之和没有大于第三边,不是三角形!!" if not (num_one -num_two <num_three or num_one - num_three or num_two - num_three < num_one): return "任意两边相减没有小于第三边,不是三角形!!" else: return "是三角形" ‘‘‘ 实现字典的fromkeys方法 ?例如: ?seq = (‘name‘, ‘age‘, ‘sex‘) ?dict = dict.fromkeys(seq, 10) ?print "New Dictionary : %s" % str(dict) ?结果:New Dictionary : {‘age‘: 10, ‘name‘: 10, ‘sex‘: 10} ‘‘‘ def print_dict_fromkeys(seq,n): num_dict = {} for i in seq: num_dict[i] = n return num_dict ‘‘‘ 键盘读入一字符串,逆序输出 ‘‘‘ def print_sorted(): num_str = input("请输入一串字符串:") print(num_str[::-1]) ‘‘‘ 读入一个整数n,输出n的阶乘 ‘‘‘ def print_jiecheng(n): num_str = ‘‘ if n ==0 or n ==1: return str(n) for i in range(1,n+1): if i == n: num_str += str(n) else: num_str += str(i)+x return num_str ‘‘‘ 打印1/2, 1/3, 1/4,….1/10 ‘‘‘ def print_chushi(n): if n ==0 or n == 1: return str(n) for i in range(2,n+1): print(1/%d%i,end= ,) ‘‘‘ 写一个函数实现一个数学公式 a**b ‘‘‘ def print_jiechenggshi(a,b): return a**b ‘‘‘ 输入数字a,n,如a,4,则打印a+aa+aaa+aaaa之和 ‘‘‘ def print_a_n(a,n): num_str = ‘‘ for i in range(1,n+1): if i==n: num_str += a*i else: num_str += a*i+"+" return num_str ‘‘‘ 求100个随机数之和,随机数要求为0—9的整数 ‘‘‘ import random def print_suijishu(): num_int = 0 for i in range(100): num_int += random.randint(1,9) return num_int ‘‘‘ 要求在屏幕上分别显求1到100之间奇数之和与偶数之和 ‘‘‘ def print_jishu_oushu_zhihe(): num_strou = ‘‘ num_strji = ‘‘ num_ou = 0 num_ji = 0 for i in range(1,101): if i %2 == 0: num_ou += i num_strou += str(i)++ if i %2 != 0: num_ji += i num_strji += str(i)++ print(偶数之和:,num_ou,奇数之和:,num_ji) print(num_strou) print(num_strji) ‘‘‘ 输入10个数,并显示最大的数与最小的数 ‘‘‘ def print_max_min_shu(lista): num_max = lista[0] num_min = lista[0] for i in lista: if i > num_max: num_max = i elif i<num_min: num_min = i print("最大的数:",num_max,"最小的数:",num_min) ‘‘‘ 给一个不多于5位的正整数,要求:一、求它是几位数,二、逆序打印出 各位数字 ‘‘‘ def print_len_sorted(n): num_str = str(n) print(len(num_str)) print(num_str[::-1]) ‘‘‘ 求1000以内的所有水仙花数(水仙花数:它的每个位上的数字的 n 次幂 之和等于它本身,例如:1^3 + 5^3+ 3^3 = 153) ‘‘‘ def print_shuixianhua(): num_int = 0 num_list = [] for i in range(1,1001): num_str = len(str(i)) for j in str(i): num_int += int(j)**num_str if num_int == int(i): num_list.append(i) num_int = 0 return num_list ‘‘‘ 编程求s=1!+2!+3!+…..+n! ‘‘‘ def print_meigeshu_jiecheng(n): num_int = 1 num_num = 0 for i in range(1,n+1): for j in range(1,i+1): num_int *= j num_num += num_int num_int = 1 print(num_num) ‘‘‘ 钞票换硬币 把一元钞票换成一分、二分、五分硬币(每种至少一枚),有多种换法,分 别有哪些? ‘‘‘ def print_huangyingbi(): num_one = 100-1-2-5 num_list = [] num_num = 0 for i in range(int(num_one/1)): for j in range(int(num_one/2)): for k in range(int(num_one/5)): if (i+2*j+k*5) == num_one: num_num += 1 num_list.append((i,j,k)) print(num_num) print(num_list) ‘‘‘ 自己实现在一句话中查找某个单词的算法,存在返回索引号,否则返回False ‘‘‘ def print_find_word(stra,strb): length = len(strb) for i in range(len(stra)): if stra[i:i+length] == strb: return i return False #print(print_find_word("you are a beautiful girl good","goods")) ‘‘‘ 读入一个十进制整数,实现十进制转二进制算法将其转成二进制数 要求:不能使用现成进制转换函数,自己写代码实现 ‘‘‘ def print_shijinzhi_erjinzhi(n): num_str = ‘‘ num_int = n while True: #print(num_str) num_str += str(int(num_int%2)) num_int = int(num_int/2) if num_int == 0: return num_str[::-1] ‘‘‘ 读入一组数字,然后把每组数字加1后输出,比如 123,输出234 ‘‘‘ def print_shuzijiayi(n): num_num = ‘‘ for i in str(n): num_num += str(int(i)+1) return num_num ‘‘‘ 随机生成10位密码 包含大小写、数字 ‘‘‘ import random import string def print_lower_upper_digit(): num_lower = list(string.ascii_lowercase) random.shuffle(num_lower) num_upper = list(string.ascii_uppercase) random.shuffle(num_upper) num_digit = list(string.digits) random.shuffle(num_digit) num_num = ‘‘.join(num_lower[:4]+num_upper[:4]+num_digit[:4]) print(num_num) #20190128 ‘‘‘ 删除一个字符串中的小写字母(map) ‘‘‘ import string def print_upper(s): num_str = ‘‘ for i in s: if i in string.ascii_uppercase: num_str += i return num_str ‘‘‘ 大于5的数字输出(filter) ‘‘‘ def print_dayu_five(num): for i in num: if int(i)>5: print(i) ‘‘‘ 找到列表中第二大的数,可以用多种方法解决 思路: 找到最大的删除掉,再找最大的 排好序找倒数第二个 遍历,声明两个变量,一个存最大的,一个存第二大的,然后逐一对比 ‘‘‘ def print_sonunt_shu(num): num_one = num[0] num_two = num[0] for i in num: if i>num_one: num_two = num_one num_one = i print(num_two) print(sorted(num)[-2]) num_max = max(num) num.remove(num_max) print(max(num)) ‘‘‘ python代码得到2个列表的交集与差集 不许用set 交集思路:遍历list1,判断是否在list2中,在的话,则存入一个列表中。 差集思路:分别遍历list1和2,如果不在对方的list中,则存入一个列表中 ‘‘‘ def print_jiaoji_chaji(lista,listb): num_inlist = [] num_notinlist = [] for i in lista: if i in listb: num_inlist.append(i) else: num_notinlist.append(i) for j in listb: if j in lista: continue elif j in num_notinlist: continue else: num_notinlist.append(j) print("交集为:",num_inlist) print("差集:",num_notinlist) ‘‘‘ 求一个字符串中的字母个数函数需判断传入参数的类型。必须使用ascii来判断是否字母 ‘‘‘ import string def print_str_geshu(): num_str = input("输入一串字符串:") num_number = 0 for i in num_str: #if i in string.ascii_letters: if (ord(i) >= 97 and ord(i) <= 122) or (ord(i)>=65 and ord(i)<=90): num_number += 1 print("传入的字符串中字母的个数为:",num_number) ‘‘‘ 写一个函数,这个函数要计算浮点数乘法的一万次相乘后的时间耗时,浮点数可以使用随机小数 ‘‘‘ import time,random def print_func(n): start_time = time.time() for i in range(n): random.random()*random.random() print(time.time()-start_time) ‘‘‘ 定义函数add(a,b)要求有个值是result来存结果 1 a,b 数字,相加 2 a,b 字符串,就当做字符串相加 3 a,b 如果list就当list相加 ‘‘‘ def print_add(a,b): result = a+b print(result) ‘‘‘ 函数参数传入5个字母,声明一个可变参数的函数,拼成一个单词 ‘‘‘ def print_pingjie(*agr): result = ‘‘ for i in agr: result += i print(result) ‘‘‘ 使用必填参数、默认参数、可变元组参数、可变字典参数(value)计算一下单词的长度之和 ‘‘‘ def print_dancichangdu(a,b=ss,*agr,**key): result = ‘‘ result += a result +=b for i in agr: result += i for v in key.values(): result += v print(a:,a) print(b:,b) print(agr:,agr) print(key:,key) print(result) ‘‘‘ 使用map把[1,2,3]变为[2,3,4] ‘‘‘ def print_map_func(x): return x+1 #print(list(map(print_map_func,[1,2,3]))) ‘‘‘ 使用map,大写变小写 ‘‘‘ def print_upper_lower(): print(list(map(lambda x:x.lower(),ABC))) print(list(map(lambda x:chr(ord(x)+32),ABC))) ‘‘‘ 打印2000-3000之间被7整除但不被5整除的数,以,(逗号)分隔 ‘‘‘ def print_five_seven(): for i in range(2000,3000): if i%7 ==0 and i%5 !=0: print(i,end=,) ‘‘‘ 2、输出9*9口诀表 ‘‘‘ def print_nine_nine(): for i in range(1,10): for j in range(1,i+1): print(str(i)+*+str(j)+=,i*j, ,end=‘‘) print() ‘‘‘ 计算1 - 1/2 + 1/3 - 1/4 + … + 1/99 - 1/100 + …直到最后一项的绝对值小于10的-5次幂为止 ‘‘‘ def print_fivemi(): result = 0.0 n = 1 while True: if abs(1/n) < pow(10,-5): break else: if n%2 ==1: result += 1/n n += 1 else: result -= 1/n n += 1 print(result) ‘‘‘ 编程将类似“China”这样的明文译成密文, 密码规律是:用字母表中原来 的字母后面第4个字母代替原来的字母,不能改变其大小写,如果超出了字母 表最后一个字母则回退到字母表中第一个字母 ‘‘‘ import sys def print_mingwen_miwen(s): result = ‘‘ if not isinstance(s,str): sys.exit(1) for i in s: if (i >= a and i<=v) or (i >= A and i<=V): result += chr(ord(i)+4) else: result += chr(ord(i)-22) print(result) ‘‘‘ 输出以下如下规律的矩阵 1 2 3 4 5 2 4 6 8 10 3 6 9 12 15 4 8 12 16 20 ‘‘‘ def print_juzh(): for i in range(1,5): for j in range(1,6): print(i*j,end= ) print() ‘‘‘ 对一个列表求和,如列表是[4, 3, 6],求和结果是 [4, 7, 13],每一项的值都等与该项的值加上前一项的值 ‘‘‘ def print_liebiaohe(lista): result = 0 num_list = [] if not isinstance(lista,list): return -1 for i in lista: num_list.append(i+result) result += i print(num_list) ‘‘‘ 一个字符串 list,每个元素是 1 个 ip,输出出现次数最多的 ip ‘‘‘ def print_ip(): num_list = ["168.1.1.1","168.1.1.1","168.1.1.2","168.1.1.3"] num_dict = {} for i in num_list: if i not in num_dict.keys(): num_dict[i] = 1 else: num_dict[i] += 1 #一句可以搞定 #num_dict[i] = num_list.count(i) for k,v in num_dict.items(): if v == max(num_dict.values()): print("出现次数最多的IP:",k) ‘‘‘ 实现一个简易版的计算器,功能要求:加、减、乘、除,支持多数同时进行计算 ‘‘‘ def print_jisuanqi(*agr): num = input("请输入你需要进行的操作,乘法*,除法/,加法+,减法-") result = 0.0 if num == *: result = 1 for i in agr: result *=i elif num == /: result = 1 for i in agr: result /= i elif num == -: result = agr[0] for i in agr[1:]: result -= i elif num == +: for i in agr: result += i else: print("输入操作符有误!!") print(result) ‘‘‘ 有一分数序列:2/1,3/2,5/3,8/5,13/8,21/13...求出这个数列的前20项之和 ‘‘‘ def print_qian_ershixiangzhihe(): num_one = 0 num_two = 1 result = 0 num = 0 num_result = 0 for i in range(1,21): result = num_one+num_two num = num_two + result num_result += num/result num_one = num_two num_two = result print("result:",result,num:,num) print(num_result) ‘‘‘ 画等(腰)边三角形(实心、空心) ‘‘‘ def print_sanjiaoxing(): for i in range(1,7): print(\n) for k in range(i,7): print( ,end=‘‘) for j in range(i): print(* ,end=‘‘) for r in range(1,7): print(\n) for s in range(r,7): print( ,end=‘‘) for l in range(r): if r >= 3 and r < 6: if l == 0 or l==r-1: print(* ,end=‘‘) else: print( ,end=‘‘) else: print(* ,end=‘‘) ‘‘‘ 画倒等边三角形 ‘‘‘ def print_daosanjiao(): for i in range(1,7): print() for k in range(i): print( ,end=‘‘) for j in range(i,7): print( *,end = ‘‘) #20190130 ‘‘‘ 要求实现一函数,该函数用于求两个集合的差集,结果集合中包含所有属于第一个集合但不属于第二个集合的元素 ‘‘‘ def print_chaji(lista,listb): num_list = [] for i in lista: if i not in listb: num_list.append(i) print("lista:",lista) print("listb:",listb) print("num_list:",num_list) ‘‘‘ 找出一段句子中最长的单词及其索引位置,以list返回 ‘‘‘ import string def print_len_zuichang(stra): for i in stra: if i in string.punctuation: stra = stra.replace(i, ) stra_list = stra.split() print(stra_list) str_word = sorted(stra.split(),key=len,reverse=True)[0] #直接一步可以求出索引: print(stra.find(sorted(stra.split(),key=len,reverse=True)[0])) print(str_word) str_index = 0 str_len = len(str_word) for j in range(len(stra)): if stra[j:j+str_len] == str_word: str_index = j return str_word,str_index ‘‘‘ 返回序列中的最大数 序列有数组、列表、字符串 ‘‘‘ def print_xulie(stra): if not isinstance(stra,(str,list,tuple)): return -1 num_one = float(stra[0]) if isinstance(stra,str): for i in stra: if float(i) > num_one: num_one = float(i) else: for j in stra: if float(j) > num_one: num_one = float(j) return num_one ‘‘‘ 把一个字典的 key,value互换 ‘‘‘ def print_jiaohuankeyvalue(dicts): dicta = {} for k,v in dicts.items(): dicta[v] = k return dicta ‘‘‘ 统计列表中列表的数量 ‘‘‘ def print_list_list(lista): num_list = 0 for i in lista: if isinstance(i,list): num_list += 1 return num_list #一句话搞定 #len(list(filter(lambda x:isinstance(x,list),[1,[2],[3],"a"]))) ‘‘‘ 删除一个列表里面所有的4 ‘‘‘ def print_del_four(lista): for i in range(lista.count(4)): lista.remove(4) return lista ‘‘‘ 删除列表中重复元素 ‘‘‘ def print_chfuyuansu(lista): for i in lista: for j in range(lista.count(i)-1): lista.remove(i) return lista ‘‘‘ 找出boy是第几个单词 ‘‘‘ def print_boy(stra): print(stra.split().index(boy)+1) ‘‘‘ 求出s中长度最长的字符串 ‘‘‘ def print_s_len(stra): print(sorted(stra.split(),key = len,reverse = True)[0]) ‘‘‘ L中分别按照学生姓名和学生成绩排序 ‘‘‘ def one(s): return s[0] def two(s): return s[1] def print_paixuone(s): print(sorted(s,key=one)) print(sorted(s,key=two)) ‘‘‘ 按照句子中每个单词的首字母进行排序,不区分大小写 ‘‘‘ def first_letter(s): return s[0].lower() def print_shouzimu(s): lista = s.split() lista.sort(key=first_letter) print(lista) ‘‘‘ 按照字符串每个数字的和进行排序 ‘‘‘ def sum(s): result = 0 for i in s: result += int(i) return result def print_sum(s): lista = s.split() lista.sort(key=sum,reverse = True) print(lista) ‘‘‘ 将两个list ,连接成[(1,4),(2,5),(3,6)] ‘‘‘ def print_two_list(lista,listb): num_list = [] for i in range(len(lista)): num_list.append((lista[i],listb[i])) print(num_list) ‘‘‘ 生成二维数组[[0, 1, 2], [3, 4, 5], [6, 7, 8]] ‘‘‘ def print_erwei_list(): num_list = [] num = 0 for i in range(3): num_num = [] for j in range(3): num_num.append(num) num += 1 num_list.append(num_num) print(num_list) ‘‘‘ 二维矩阵转置 ‘‘‘ def print_juzhengzhuanzhi(): a=[ [1,2,3], [4,5,6], [7,8,9], [10,11,12] ] num_list = [] for i in range(3): num_num = [] for j in a: num_num.append(j[i]) num_list.append(num_num) print(num_list) ‘‘‘ 删除二维矩阵的第1列 ‘‘‘ def print_shchujuzhdiyilie(): a=[ [1,2,3], [4,5,6], [7,8,9], [10,11,12] ] num_list = [] for i in a: num_num = [] for j in range(1,3): num_num.append(i[j]) num_list.append(num_num) print(num_list) ‘‘‘ 把一个列表偶数位作为key,奇数位作为value,转换成字典 ‘‘‘ def print_oushulie_key(lista): num_dict = {} for i in range(1,len(lista),2): num_dict[lista[i]] = lista[i-1] print(num_dict) ‘‘‘ 有一个长度为101的数组,存在1-100的数字,有一个是重复的,找出这个重复的数字 ‘‘‘ def print_chfushuzi(lista): for i in lista: if lista.count(i) >=2: print(i) break ‘‘‘ 两个长度相同的list,一个里面的做字典的key,一个里面做字典的value,请写个函数实现 ‘‘‘ def print_dict_key_value(lista,listb): num_dict = {} for i in range(len(lista)): num_dict[lista[i]] = listb[i] print(num_dict) ‘‘‘ 统计一个字符串中每一个字母累计出现的次数 ‘‘‘ def print_tjizicxiancishu(stra): num_dict = {} for i in stra: if i not in num_dict.keys(): num_dict[i] = 1 else: num_dict[i] += 1 print(num_dict) ‘‘‘ 统计一个字符串中每个单词出现的次数 ‘‘‘ def print_dancicxiancishu(stra): num_dict = {} num = stra.split() for i in num: num_dict[i] = num.count(i) print(num_dict) ‘‘‘ 从键盘输入两个数,并比较其大小,直到输入e/E退出程序 ‘‘‘ def print_caidaxiao(): while True: num_one = input("请输入第一个要比较的数:") num_two= input("请输入第二个要比较的数:") if num_one in eE or num_two in eE: print("结束并退出!!") break elif int(num_one) > int(num_two): print("第一个数大于第二个数") elif int(num_one) < int(num_two): print("第一个数小于第二个数") else: print("两个数相等!!") ‘‘‘ 将列表元素交替地作为建和值来创建字典 ‘‘‘ def print_jiaotizuo_key_values(lista): num_dict = {} for i in range(0,len(lista),2): num_dict[lista[i]] = lista[i+1] print(num_dict) ‘‘‘ 分别输出字符串中奇数坐标和偶数坐标的字符 ‘‘‘ def print_jishu_oushu_zuobiao(stra): num_list = [[],[]] for i in range(len(stra)): if i%2 ==0: num_list[0].append(stra[i]) else: num_list[1].append(stra[i]) print("奇数坐标的字符为:",num_list[1]) print("偶数坐标的字符为:",num_list[0]) ‘‘‘ 将一个字典的 key和value 互换 ‘‘‘ def print_jiaohuan_value_key(dicta): num_dict = {} for k,v in dicta.items(): num_dict[v] = k print("原始的字典:",dicta) print("转换后的字典:",num_dict) ‘‘‘ 将一个多重嵌套的列表的元素进行互换,存到另一个同等维度的嵌套列表中,例如:[[1,2,3],[4,5,6]]互换后变成[[1,4],[2,5],[3,6]] ‘‘‘ def print_lista_listb(lista): num_listb = [] for i in range(len(lista[0])): num_num = [] for j in range(len(lista)): num_num.append(lista[j][i]) num_listb.append(num_num) print(num_listb) ‘‘‘ 有一个3 x 4的矩阵,要求编程求出其中值最大的那个元素的值,以及其所在的行号和列号,矩阵可以通过嵌套列表来模拟 ‘‘‘ def print_sanchengsi_zuidazhi(): a = [ [1,2,3], [4,30,6], [7,8,9], [10,11,12] ] num_num = a[0][0] num_one = 0 num_two = 0 for i in range(len(a)): for j in range(len(a[i])): if a[i][j] > num_num: num_one = i num_two = j num_num = a[i][j] print("最大的元素为%d,行号为%d,列号为%d!"%(num_num,num_one+1,num_two+1)) ‘‘‘ 递归实现嵌套列表求和 ‘‘‘ def print_list_qiantao_qiuhe(lista): num_num = 0 for i in lista: if not isinstance(i,list): num_num += i else: num_num += print_list_qiantao_qiuhe(i) return num_num if __name__=="__main__": pass

 

#encoding=utf-8
‘‘‘
使锟斤拷raw_input锟斤拷锟斤拷锟斤拷锟斤拷锟斤拷锟?
‘‘‘
str = int(raw_input(u‘锟斤拷锟斤拷锟斤拷锟斤拷某杉锟斤拷锟?‘))
‘‘‘
使锟矫匡拷锟斤拷锟斤拷锟斤拷锟?
‘‘‘
if str >= 90:
    print ‘A‘
elif str >=60 and str < 90:
    print ‘B‘
elif str < 60 and str != 0:
    print ‘C‘
‘‘‘
锟叫憋拷锟绞癸拷茫锟斤拷斜锟绞癸拷锟斤拷锟斤拷锟斤拷沤锟斤拷卸锟斤拷澹匡拷锟皆拷锟街拷锟绞癸拷枚锟斤拷欧锟斤拷锟斤拷锟斤拷锟斤拷锟斤拷锟轿拷斜锟绞癸拷枚锟斤拷锟斤拷锟斤拷锟脚斤拷锟斤拷嵌锟斤拷锟斤拷锟斤拷示锟斤拷锟斤拷
‘‘‘
name = [‘foster‘,‘foe‘,‘lily‘,‘mickel‘,‘live‘,‘moon‘,‘ruby‘
,‘cindy‘,‘miya‘]
 
‘‘‘
锟斤拷印双锟斤拷锟脚★拷锟斤拷锟斤拷锟脚★拷锟斤拷锟斤拷锟斤拷锟脚匡拷锟斤拷使锟斤拷\转锟斤拷锟斤拷锟斤拷锟阶拷锟?
‘‘‘
print "锟斤拷锟斤拷锟脚o拷\‘;双锟斤拷锟脚o拷\";锟斤拷锟斤拷锟斤拷:\‘\‘\‘"
‘‘‘
锟斤拷值锟侥硷拷锟姐,锟斤拷锟皆碉拷锟斤拷锟斤拷锟斤拷锟斤拷锟斤拷也锟斤拷锟斤拷使锟斤拷def锟斤拷锟斤拷锟斤拷锟斤拷锟矫诧拷锟斤拷锟截硷拷锟斤拷锟街碉拷锟絛ef锟斤拷锟斤拷锟叫匡拷锟斤拷直锟接革拷锟斤拷锟斤拷锟斤拷值锟斤拷锟叫诧拷锟斤拷锟斤拷值锟侥o拷锟斤拷锟斤拷要锟矫伙拷锟斤拷锟轿o拷直锟斤拷默锟较匡拷始锟斤拷锟斤拷牟锟斤拷锟?
‘‘‘
length = 10
breath = 5
area = length*breath
 
def getArea(length,breath):
    return length*breath
 
print getArea(length,breath)
 
 
def getAdd(sun1,sun2):
    return sun1+sun2
print getAdd(2046,9876)
 
def getArea1(length,breath=7):
    return length*breath
print getArea1(2)
 
sun1 =int(raw_input(u‘锟斤拷锟斤拷锟斤拷学锟斤拷锟侥凤拷锟斤拷锟斤拷‘))
if sun1 < 0 or sun1 > 100:
    print u‘锟斤拷锟斤拷锟斤拷锟斤拷‘
elif sun1 >= 60:
    print u‘锟斤拷喜锟姐及锟斤拷锟剿o拷锟斤拷锟斤拷锟角o拷‘,sun1
else:
    print u‘锟斤拷锟斤拷锟斤拷思锟斤拷锟姐不锟斤拷锟今,凤拷锟斤拷锟角o拷‘,sun1
listA = [12,‘1sdd‘,2,4]
print listA
shopList = [‘apple‘,‘mongo‘,‘carrot‘,‘banana‘]
print ‘I have ‘,len(shopList),‘ items to buy‘
 
 
‘‘‘
使锟斤拷type锟斤拷锟斤拷取锟斤拷锟斤拷锟斤拷锟斤拷锟斤拷锟斤拷锟斤拷停锟斤拷斜锟斤拷锟斤拷锟斤拷使锟斤拷sort()锟斤拷锟斤拷锟斤拷sort锟斤拷锟斤拷没锟叫凤拷锟斤拷值锟斤拷锟斤拷要锟斤拷锟斤拷锟斤拷锟劫斤拷锟斤拷使锟矫o拷使锟斤拷append()锟斤拷锟斤拷锟斤拷锟斤拷锟叫憋拷锟阶凤拷樱锟街伙拷锟阶凤拷拥锟斤拷锟皆拷兀锟绞癸拷锟絜xtend()锟斤拷锟斤拷锟斤拷追锟斤拷锟斤拷锟斤拷锟叫憋拷锟斤拷锟斤拷锟斤拷锟斤拷斜锟较诧拷锟斤拷一锟斤拷
‘‘‘
print type(shopList)
for items in shopList:
    print items
shopList.append(‘rice‘)
print shopList
shopList.sort()
print u‘锟斤拷锟斤拷锟侥癸拷锟斤拷锟藉单锟斤拷‘,shopList
zifulist = [u‘unicode锟街凤拷‘,‘锟街凤拷锟斤拷‘,12,12.34,]
for i in zifulist:
    print i ,u‘锟街凤拷锟斤拷锟酵o拷‘,type(i)
listA = [1,2,3]
listB = [4,5,6]
listA.extend(listB)
print u‘锟铰碉拷锟叫憋拷锟?‘,listA
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 

python习题20190130

标签:ping   嵌套循环   包括   jin   支付   cheng   ==   计算   输入数据   

原文地址:https://www.cnblogs.com/xiaoloinzi/p/10338995.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有
迷上了代码!