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Java复数的加乘除运算

时间:2019-03-20 01:24:15      阅读:150      评论:0      收藏:0      [点我收藏+]

标签:turn   new   rate   dep   a*   指正   rgs   lex   javac   

//主要是对零的处理,有什么不对的地方欢迎批评指正,一起进步
class
complex{ double a,b; public String toString() { return("实部:"+a+"虚部:"+b); } void add(complex x,complex y) { double m,n; m = x.a+y.a; n = x.b+y.b; print(m,n); } void mult(complex x,complex y) { double m,n; n = x.b*y.a+x.a*y.b; m =x.a*y.a-x.b*y.b; print(m,n); } void dep(complex x,complex y) { double n = (x.a*y.a-x.b*y.b)/(y.a*y.a+y.b*y.b); double m = (x.b*y.a+x.a*y.b)/(y.a*y.a+y.b*y.b); if(y.a==0&&y.b==0) System.out.println("除法无意义\n"); else { print(m,n); } } void print(double m,double n) { if(m!=0) { if(n>0) { System.out.println(m+"+"); System.out.println(n+"i"); } else if(n<0) { System.out.print(m); System.out.println(n+"i"); } else System.out.println(m); } else { if(n!=0) { System.out.println(n+"i"); } else System.out.println(m); } } } public class Javacomplex { public static void main(String[] args) { // TODO Auto-generated method stub complex n1,n2,n; n1 = new complex(); n2 = new complex(); n = new complex(); n1.a = 1;n1.b=2; n2.a = -1;n2.b = 1; System.out.println(n1.toString()); System.out.println(n2.toString()); n.add(n1, n2); n.mult(n1, n2); n.dep(n1, n2); } }

 

Java复数的加乘除运算

标签:turn   new   rate   dep   a*   指正   rgs   lex   javac   

原文地址:https://www.cnblogs.com/kmxojer/p/10562395.html

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