sql查询连续3天有交易记录的客户

with t as (
    select 
        cus_id
        ,txn_dt
    from a
    qualify row_number()over(partition by cus_id,txn_dt order by id ) = 1
              )
select
    cus_id   
from t m
inner join t n
on m.cus_id = n.cus_id
and m.txn_dt <= n.txn_dt +2
group by 1
having count(cus_id) = 3
;
--或者
select
    cus_id   
from a m
inner join a n
on m.cus_id = n.cus_id
and m.txn_dt <= n.txn_dt +2
group by 1
having count(distinct txn_dt) = 3
;