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HackerRank【SQL3】

时间:2019-07-22 13:27:58      阅读:134      评论:0      收藏:0      [点我收藏+]

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1、Higher Than 75 Marks

Query the Name of any student in STUDENTS who scored higher than 75 Marks. Order your output by the last three charactersof each name. If two or more students both have names ending in the same last three characters (i.e.: Bobby, Robby, etc.), secondary sort them by ascending ID.

The STUDENTS table is described as follows: 

技术图片

 

Sample Output

Ashley
Julia
Belvet

Explanation

Only Ashley, Julia, and Belvet have Marks > 75. If you look at the last three characters of each of their names, there are no duplicates and ‘ley‘ < ‘lia‘ < ‘vet‘.

select Name from STUDENTS WHERE Marks > 75 order by right(Name, 3), ID ASC;

 

2、Employee Names

Write a query that prints a list of employee names (i.e.: the name attribute) from the Employee table in alphabetical order.

Input Format

The Employee table containing employee data for a company is described as follows:

技术图片

where employee_id is an employee‘s ID number, name is their name, months is the total number of months they‘ve been working for the company, and salary is their monthly salary.

Sample Output

Angela
Bonnie
Frank
Joe
Kimberly
Lisa
Michael
Patrick
Rose
Todd

select Name from Employee order by  CONVERT (Name USING utf8);

3、Employee Salaries

Write a query that prints a list of employee names (i.e.: the name attribute) for employees in Employee having a salary greater than $2000 per month who have been employees for less than 10 months. Sort your result by ascending employee_id.

 

Input Format

The Employee table containing employee data for a company is described as follows:

技术图片

where employee_id is an employee‘s ID number, name is their name, months is the total number of months they‘ve been working for the company, and salary is the their monthly salary.

Sample Input

技术图片

Sample Output

Angela
Michael
Todd
Joe

select Name from Employee where salary > 2000 and months<10 order by employee_id;

 

HackerRank【SQL3】

标签:image   scree   number   hack   nta   ack   sel   etc   rac   

原文地址:https://www.cnblogs.com/wzs-python/p/11225129.html

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