li = ["李嘉诚", "麻花藤", "?海峰", "刘嘉玲"]
s = "_".join(li)
print(s)

li = "?花?闺?"
s = "_".join(li)
print(s)

li = [11, 22, 33, 44]
for e in li:
　　 li.remove(e)
print(li)

结果:
[22, 44]

li = [11, 22, 33, 44]
for i in range(0, len(li)):
　　del li[i]
print(li)

结果: 报错
# i= 0, 1, 2 删除的时候li[0] 被删除之后. 后??个就变成了第0个.
# 以此类推. 当i = 2的时候. list中只有?个元素. 但是这个时候删除的是第2个 肯定报错啊

li = [11, 22, 33, 44]
del_li = []
for e in li:
　　 del_li.append(e)
for e in del_li:
　　 li.remove(e)
print(li)

dic = dict.fromkeys(["jay", "JJ"], ["周杰伦", "麻花藤"])
print(dic)

dic.get("jay").append("胡?")
print(dic)

结果:
{‘jay‘: [‘周杰伦‘, ‘麻花藤‘, ‘胡?‘], ‘JJ‘: [‘周杰伦‘, ‘麻花藤‘, ‘胡?‘]}

dic = {‘k1‘: ‘alex‘, ‘k2‘: ‘wusir‘, ‘s1‘: ‘??板‘}
dic_del_list = []
# 删除key中带有‘k‘的元素
for k in dic:
　　if ‘k‘ in k:
　　　　 dic_del_list.append(k)


for el in dic_del_list:
　　del dic[el]
print(dic)

set1 = {‘1‘,‘alex‘,2,True,[1,2,3]} # 报错
set2 = {‘1‘,‘alex‘,2,True,{1:2}} # 报错
set3 = {‘1‘,‘alex‘,2,True,(1,2,[2,3,4])} # 报错

s = {"周杰伦", "周杰伦", "周星星"}
print(s)

结果:
{‘周星星‘, ‘周杰伦‘}

s = {"刘嘉玲", ‘关之琳‘, "王祖贤"}
s.add("郑裕玲")
print(s)

s.add("郑裕玲") # 重复的内容不会被添加到set集合中
print(s)

s = {"刘嘉玲", ‘关之琳‘, "王祖贤"}
s.update("麻花藤") # 迭代更新
print(s)

s.update(["张曼?", "李若彤","李若彤"])
print(s)

s = {"刘嘉玲", ‘关之琳‘, "王祖贤","张曼?", "李若彤"}
item = s.pop() # 随机弹出?个.
print(s)
print(item)

s.remove("关之琳") # 直接删除元素
# s.remove("??疼") # 不存在这个元素. 删除会报错
print(s)

s.clear() # 清空set集合.需要注意的是set集合如果是空的. 打印出来是set() 因为要和
dict区分的.
print(s) # set()

# set集合中的数据没有索引. 也没有办法去定位?个元素. 所以没有办法进?直接修改. 
# 我们可以采?先删除后添加的?式来完成修改操作
s = {"刘嘉玲", ‘关之琳‘, "王祖贤","张曼?", "李若彤"}
# 把刘嘉玲改成赵本?
s.remove("刘嘉玲")
s.add("赵本?")
print(s)

# set是?个可迭代对象. 所以可以进?for循环
for el in s:
　　print(el)

s1 = {"刘能", "赵四", "???"}
s2 = {"刘科?", "冯乡?", "???"}


# 交集
# 两个集合中的共有元素
print(s1 & s2) # {‘???‘}
print(s1.intersection(s2)) # {‘???‘}

# 并集
print(s1 | s2) # {‘刘科?‘, ‘冯乡?‘, ‘赵四‘, ‘???‘, ‘刘能‘}
print(s1.union(s2)) # {‘刘科?‘, ‘冯乡?‘, ‘赵四‘, ‘???‘, ‘刘能‘}

# 差集
print(s1 - s2) # {‘赵四‘, ‘刘能‘} 得到第?个中单独存在的
print(s1.difference(s2)) # {‘赵四‘, ‘刘能‘}

# 反交集
print(s1 ^ s2) # 两个集合中单独存在的数据 {‘冯乡?‘, ‘刘能‘, ‘刘科?‘, ‘赵四‘}
print(s1.symmetric_difference(s2)) # {‘冯乡?‘, ‘刘能‘, ‘刘科?‘, ‘赵四‘}

s1 = {"刘能", "赵四"}
s2 = {"刘能", "赵四", "???"}

# ?集
print(s1 < s2) # set1是set2的?集吗? True
print(s1.issubset(s2))

# 超集
print(s1 > s2) # set1是set2的超集吗? False
print(s1.issuperset(s2))

s = frozenset(["赵本?", "刘能", "???", "?跪"])

dic = {s:‘123‘} # 可以正常使?了
print(dic)

lst1 = ["??狮王", "紫衫?王", "?眉鹰王", "?翼蝠王"]
lst2 = lst1


print(lst1)
print(lst2)

lst1.append("杨逍")
print(lst1)
print(lst2)

结果:
[‘??狮王‘, ‘紫衫?王‘, ‘?眉鹰王‘, ‘?翼蝠王‘, ‘杨逍‘]
[‘??狮王‘, ‘紫衫?王‘, ‘?眉鹰王‘, ‘?翼蝠王‘, ‘杨逍‘]

dic1 = {"id": 123, "name": "谢逊"}
dic2 = dic1
print(dic1)
print(dic2)

dic1[‘name‘] = "范瑶"
print(dic1)
print(dic2)

结果:
{‘id‘: 123, ‘name‘: ‘谢逊‘}
{‘id‘: 123, ‘name‘: ‘谢逊‘}
{‘id‘: 123, ‘name‘: ‘范瑶‘}
{‘id‘: 123, ‘name‘: ‘范瑶‘}