标签：evel lower nbsp ESS for inpu div name eve
1.Given a Huffman tree for N (≥2) characters, all with different weights. The weight of any non-leaf node must be no less than the weight of any node on the next lower level.
2.Let C be an alphabet in which each character c in C has frequency c.freq. If the size of C is n, the length of the optimal prefix code for any character c is not greater than n?1.
3.哈夫曼编码是一种最优的前缀码。对一个给定的字符集及其字符频率，其哈夫曼编码不一定是唯一的，但是每个字符的哈夫曼码的长度一定是唯一的。
标签：evel lower nbsp ESS for inpu div name eve
原文地址：https://www.cnblogs.com/nonlinearthink/p/11811905.html
