MySQL 某列数据所占总和百分比 SQL实例

标签：address   person   from   round   sel   mysq   mysql   sql   res   

SELECT a.address,
a.cont AS countAddress,
b.sum AS sumAddress,
CONCAT( ROUND( a.cont / b.sum * 100, 2 ), ‘‘, ‘%‘ ) AS percent
FROM
( SELECT address, COUNT( address ) AS cont FROM person_base_info GROUP BY address ) a,
(SELECT COUNT(*) AS sum FROM person_base_info ) b

MySQL 某列数据所占总和百分比 SQL实例

标签：address   person   from   round   sel   mysq   mysql   sql   res   

原文地址：https://www.cnblogs.com/magichu/p/14770788.html