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Since arrays are always passed by reference, all changes made to the array elements inside the function will be made to the original array.
int ProcessValues (int [], int ); // works with ANY 1-d array
Example:
#include <iostream> using namespace std; int SumValues (int [], int ); //function prototype void main( ) { int Array[10]={0,1,2,3,4,5,6,7,8,9}; int total_sum; total_sum = SumValues (Array, 10); //function call cout <<”Total sum is “ <<total_sum; } int SumValues (int values[], int num_of_values) //function header { int sum = 0; for( int i=0; i < num_of_values; i++) sum+=values[i]; return sum; }
The only way to protect the elements of the array from being inadvertently changed, is to declare an array to be a const parameter.
#include <iostream> using namespace std; int SumValues (const int [], int); //function prototype int main( ) { const int length =10; int Array[10]={0,1,2,3,4,5,6,7,8,9}; int total_sum; total_sum = SumValues (Array, length); //function call cout <<”Total sum is “ <<total_sum; return 0; } int SumValues (const int values[], int num_of_values) //function header { int sum = 0; for( int i=0; i < num_of_values; i++) sum+=values[i]; return sum; }
Reference:
http://stackoverflow.com/questions/23035407/passing-1d-and-2d-arrays-by-reference-in-c
http://doursat.free.fr/docs/CS135_S06/CS135_S06_8_1D_Arrays2.pdf
传入一维数组到函数 Passing 1D array to function
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原文地址：http://www.cnblogs.com/learnopencad/p/4314724.html
