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dataDiff 多用于获取指定时间间隔内的数据集，如：
select count(1) as col2 from ComplaintMain cm where DateDiff(dd,cm.CreatedOn,getDate())<=7 and cm.HandlingBy=" + (int)HandlingBy.MemberCD + @" and cm.CState=" + (int)ComplaintState.Successfully + ";";
上面的query是获取一周内条件数据；
函数方法：
DATEDIFF ( datepart , startdate , enddate )
datepart参数：
|
datepart |
Abbreviations |
|---|---|
|
year |
yy, yyyy |
|
quarter |
qq, q |
|
month |
mm, m |
|
dayofyear |
dy, y |
|
day |
dd, d |
|
week |
wk, ww |
|
hour |
hh |
|
minute |
mi, n |
|
second |
ss, s |
|
millisecond |
ms |
|
microsecond |
mcs |
|
nanosecond |
ns |
demo:
SELECT DATEDIFF(year, ‘2005-12-31 23:59:59.9999999‘ , ‘2006-01-01 00:00:00.0000000‘); SELECT DATEDIFF(quarter, ‘2005-12-31 23:59:59.9999999‘ , ‘2006-01-01 00:00:00.0000000‘); SELECT DATEDIFF(month, ‘2005-12-31 23:59:59.9999999‘ , ‘2006-01-01 00:00:00.0000000‘); SELECT DATEDIFF(dayofyear, ‘2005-12-31 23:59:59.9999999‘ , ‘2006-01-01 00:00:00.0000000‘); SELECT DATEDIFF(day, ‘2005-12-31 23:59:59.9999999‘ , ‘2006-01-01 00:00:00.0000000‘); SELECT DATEDIFF(week, ‘2005-12-31 23:59:59.9999999‘ , ‘2006-01-01 00:00:00.0000000‘); SELECT DATEDIFF(hour, ‘2005-12-31 23:59:59.9999999‘ , ‘2006-01-01 00:00:00.0000000‘); SELECT DATEDIFF(minute, ‘2005-12-31 23:59:59.9999999‘ , ‘2006-01-01 00:00:00.0000000‘); SELECT DATEDIFF(second, ‘2005-12-31 23:59:59.9999999‘ , ‘2006-01-01 00:00:00.0000000‘); SELECT DATEDIFF(millisecond, ‘2005-12-31 23:59:59.9999999‘ , ‘2006-01-01 00:00:00.0000000‘);
例子：
CREATE TABLE dbo.Duration ( startDate datetime2 ,endDate datetime2 ); INSERT INTO dbo.Duration(startDate,endDate) VALUES(‘2007-05-06 12:10:09‘,‘2007-05-07 12:10:09‘); SELECT DATEDIFF(day,startDate,endDate) AS ‘Duration‘ FROM dbo.Duration; -- Returns: 1
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原文地址：http://www.cnblogs.com/xiguain/p/4424383.html
