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1、代码如下：
void TestCache(otl_connect& otlConn) { try { char sql[1024] = {0}; sprintf(sql,"call test1(1)"); otl_stream stream(100, sql, otlConn,otl_implicit_select); int id; while(!stream.eof()) { stream>>id; char sql2[1024] = {0}; sprintf(sql2,"call test2(:Id<int>)"); otl_stream stream2(100, sql2, otlConn,otl_implicit_select); stream2<<id; while(!stream2.eof()) { int ff =0; } } } catch(otl_exception& ex) { printf("ExecuteSql Error, ErrorMsg[%s], Sql[%s]", ex.msg, ex.stm_text); } }
2、执行otl_stream stream2(100, sql2, otlConn,otl_implicit_select);的时候出错，如下：
Commands out of sync; you can‘t run this command now
3、错误原因：mysql上一次的查询没有将结果集释放掉，又进行下一次的查询。
4、otl：在第一个stream读取期间，第二个stream使用了绑定变量，会导致上面的问题，不知道otl内部是怎么封装的。
5、解决办法：
a、第二个stream不使用绑定变量，如下：
void TestCache(otl_connect& otlConn) { try { char sql[1024] = {0}; sprintf(sql,"call test1(1)"); otl_stream stream(100, sql, otlConn,otl_implicit_select); int id; while(!stream.eof()) { stream>>id; char sql2[1024] = {0}; sprintf(sql2,"call test2(%d)",id); otl_stream stream2(100, sql2, otlConn,otl_implicit_select); while(!stream2.eof()) { int ff =0; } } } catch(otl_exception& ex) { printf("ExecuteSql Error, ErrorMsg[%s], Sql[%s]", ex.msg, ex.stm_text); } }
b、先把第一个stream读取完，再进行第二个stream，如下：
void TestCache(otl_connect& otlConn) { try { char sql[1024] = {0}; sprintf(sql,"call test1(1)"); otl_stream stream(100, sql, otlConn,otl_implicit_select); vector<int> intVec; int id; while(!stream.eof()) { stream>>id; intVec.push_back(id); } for(vector<int>::iterator iter = intVec.begin(); iter != intVec.end(); ++iter) { char sql2[1024] = {0}; sprintf(sql2,"call test2(:Id<int>)"); otl_stream stream2(100, sql2, otlConn,otl_implicit_select); stream2<<id; while(!stream2.eof()) { int ff =0; } } } catch(otl_exception& ex) { printf("ExecuteSql Error, ErrorMsg[%s], Sql[%s]", ex.msg, ex.stm_text); } }
使用otl，报错：mysql Commands out of sync; you can't run this command now
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原文地址：http://www.cnblogs.com/nzbbody/p/4540738.html
