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/* 题目如下: 1 (for 循环)*编程找出四位整数abcd 中满足下述关系的数。 (ab+cd)(ab+cd)=abcd 2 (循环)*读入一个整数n,输出如下图形 n = 3 * *** ***** n = 4 * *** ***** ******* 思路:读入的整数n,就是外层循环的循环次数。 对于每一行,要做的事情:1. 输出若干个空格;2. 输出若干个星;3. 换行。 提示:输出不换行,用System.out.print() 3. (循环)**求水仙花数。所谓水仙花数,是指一个三位数abc,如果满足a3+b3+c3=abc,则abc 是水仙花数。 4. (循环)**输入一个整数,计算它各位上数字的和。(注意:是任意位的整数) 空格: n-1 依次递减 星号: 1 3 5 7 1 2 3 4 */ package MyTest; import java.util.Scanner; public class ChapUnitOne { //第一题答案 public void AnswerOne() { int a,b,c,d; /* int i = 1234; a = i / 1000; b = i / 100 % 10; c = i / 10 % 10; d = i % 10; System.out.println(a); System.out.println(b); System.out.println(c); System.out.println(d); */ for(int i = 1000;i<9999;i++) { a = i / 1000; b = i / 100 % 10; c = i / 10 % 10; d = i % 10; int ab = a*10+b; int cd = c*10+d; int ad = ab+cd; if(ad*ad == i) { System.out.println(i); } } } //第二题答案 public void AnswerTwo() { Scanner num = new Scanner(System.in); System.out.println("请输入一个整数"); int mynum = num.nextInt(); for(int i=0; i<mynum; i++) { for (int j=0; j<=mynum-i-1; j++) { System.out.print(" "); } for (int j=0; j<=i*2; j++) { System.out.print("*"); } System.out.println(); } } //第三题答案 public void AnswerThree() { for(int i = 100;i<999;i++) { int a = i / 100 % 10; int b = i / 10 % 10; int c = i % 10; if(a*a*a+b*b*b+c*c*c == i) { System.out.println("该数字为水仙花数:"+i); } } } //第四题答案 public void AnswerFour() { Scanner num = new Scanner(System.in); System.out.println("请输入一个整数:"); int mynum = num.nextInt(); int sum = 0; /* int a = i / 100 % 10; int b = i / 10 % 10; int c = i % 10; */ System.out.print("Sum = "); while (mynum>0) { int temp = mynum%10; sum += mynum%10; mynum = mynum/10; if(mynum !=0 ) System.out.print(temp+"+"); else System.out.print(temp); } System.out.println(" = "+sum); } public static void main(String[] args) { Scanner i = new Scanner(System.in); System.out.println("请输入您想查看答案的题号:"); int num = i.nextInt(); ChapUnitOne myanswer = new ChapUnitOne(); switch(num) { case 1: myanswer.AnswerOne(); break; case 2: myanswer.AnswerTwo(); break; case 3: myanswer.AnswerThree(); break; case 4: myanswer.AnswerFour(); break; } } }
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原文地址:http://www.cnblogs.com/IamJiangXiaoKun/p/4627501.html