标签:
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 4504 Accepted Submission(s): 1838
#include<stdio.h>
#include<string.h>
#include<queue>
#include<algorithm>
using namespace std;
bool cmp(int a,int b)
{
return a>b;
}
int str[100010];
int main()
{
int n,m,j,i,s,t;
while(scanf("%d%d",&n,&m)&&n!=0&&m!=0)
{
for(i=0;i<n;i++)
{
scanf("%d",&str[i]);
}
sort(str,str+n,cmp);
if(n>m)
{
for(i=0;i<m;i++)
{
if(i==0)
printf("%d",str[i]);
else
printf(" %d",str[i]);
}
printf("\n");
}
else
{
for(i=0;i<n;i++)
{
if(i==0)
printf("%d",str[i]);
else
printf(" %d",str[i]);
}
printf("\n");
}
}
return 0;
}
优先队列:
#include<stdio.h>
#include<queue>
using namespace std;
int main()
{
int n,m,j,i,t,k;
while(scanf("%d%d",&n,&m)&&n!=0&&m!=0)
{
priority_queue<int>q;
int c=n;
while(c--)
{
scanf("%d",&t);
q.push(t);
}
if(n<m)
{
k=n;n=m;m=k;
}
int a=n-m;
int p=0;
while(q.size()>a)
{
if(p==0)
printf("%d",q.top());
else
printf(" %d",q.top());
p++;
q.pop();
}
printf("\n");
}
return 0;
}
标签:
原文地址:http://www.cnblogs.com/tonghao/p/4683474.html