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链接:
http://poj.org/problem?id=2349
代码:
#include <cstdio> #include <cstring> #include <cstdlib> #include <cmath> #include <iostream> #include <algorithm> using namespace std; const int N = 510; const int INF = 0xfffffff; struct node { int x, y; }s[N]; int n; double ss[N]; double J[N][N], dist[N]; bool vis[N]; void Prim() { int i, j; dist[1]=0; memset(vis, 0, sizeof(vis)); vis[1]=1; for(i=1; i<=n; i++) dist[i]=J[1][i]; for(i=1; i<n; i++) { int index=1; double MIN=INF; for(j=1; j<=n; j++) { if(!vis[j] && dist[j]<MIN && dist[j]) { index=j; MIN=dist[j]; } } vis[index]=1; ss[index] = MIN; for(j=1; j<=n; j++) { if(!vis[j] && dist[j]>J[index][j]) dist[j]=J[index][j]; } } } int main () { int t; scanf("%d", &t); while(t--) { int m, i, j; scanf("%d%d", &m, &n); memset(s, 0, sizeof(s)); memset(ss, 0, sizeof(ss)); for(i=1; i<=n; i++) scanf("%d%d", &s[i].x, &s[i].y); for(i=1; i<=n; i++) for(j=1; j<=n; j++) { double k=sqrt(1.0*(s[i].x-s[j].x)*(s[i].x-s[j].x)+1.0*(s[i].y-s[j].y)*(s[i].y-s[j].y)); J[i][j]=J[j][i]=k; } Prim(); sort(ss+1, ss+n+1); printf("%.2f\n", ss[n-m+1]); } return 0; }
(最小生成树) Arctic Network -- POJ --2349
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原文地址:http://www.cnblogs.com/YY56/p/4735098.html