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Time Limit: 5000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 42716 Accepted Submission(s): 18715
2 1 1 2 3 3 3 1 2 5 2 3 5 3 1 2 0 0
3 2
#include<cstdio>
#include<cstring>
#define max 110
#define INF 0x3f3f3f
int n,map[max][max];//map记录两点间的最短路径
void dijkstra()
{
int dis[max];//记录起始点到当前点的最短路径
int visit[max];//标记是否访问过了
int i,j,next,min;
memset(visit,0,sizeof(visit));
for(i=1;i<=n;i++)
dis[i]=map[1][i];
visit[1]=1;
for(i=2;i<=n;++i)
{
min=INF;
for(j=1;j<=n;++j)
{
if(visit[j]==0&&min>dis[j])
{
min=dis[j];
next=j;
}
}
visit[next]=1;
for(j=1;j<=n;j++)
{
if(visit[j]==0&&dis[j]>dis[next]+map[next][j])
dis[j]=dis[next]+map[next][j];
}
}
printf("%d\n",dis[n]);
}
int main()
{
int m,a,b,c;
while(scanf("%d%d",&n,&m)&&n||m)
{
memset(map,INF,sizeof(map));
while(m--)
{
scanf("%d%d%d",&a,&b,&c);
if(map[a][b]>c)
map[a][b]=map[b][a]=c;
}
dijkstra();
}
return 0;
}版权声明:本文为博主原创文章,未经博主允许不得转载。
HDOJ 2544 最短路(最短路径 dijkstra算法)
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原文地址:http://blog.csdn.net/zwj1452267376/article/details/47729727