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Android实现后台长期监听时间变化
1.首先我们的目的是长期监听时间变化,其实应用程序退出。 通过了解我们知道注册ACTION_TIME_TICK广播接收器可以监听系统事件改变,但是 查看SDK发现ACTION_TIME_TICK广播事件只能动态注册: Broadcast Action: The current time has changed. Sent every minute. You can not receive t...
分类:移动开发   时间:2014-06-05 08:35:13    阅读次数:285
LeetCode: Search a 2D Matrix [074]
【题目】 Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted from left to right. The first integer of each row is greater than the last integer of the previous ...
分类:其他好文   时间:2014-06-05 08:28:43    阅读次数:321
poj 3278
Catch That Cow Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 43851   Accepted: 13674 Description Farmer John has been informed of the location of a fugitiv...
分类:其他好文   时间:2014-06-05 07:45:38    阅读次数:220
POJ 3259 Wormholes (图论---最短路 Bellman-Ford || SPFA)
链接:http://poj.org/problem?id=3259 Description While exploring his many farms, Farmer John has discovered a number of amazing wormholes. A wormhole is very peculiar because it is a one-way path t...
分类:其他好文   时间:2014-06-05 05:26:33    阅读次数:240
LeetCode: Valid Number [066]
【题目】 Validate if a given string is numeric. Some examples: "0" => true " 0.1 " => true "abc" => false "1 a" => false "2e10" => true Note: It is intended for the problem statement to be ambiguous. You should gather all requirements up front before imple...
分类:其他好文   时间:2014-06-04 23:45:09    阅读次数:388
LeetCode: Text Justification [068]
【题目】 Given an array of words and a length L, format the text such that each line has exactly L characters and is fully (left and right) justified. You should pack your words in a greedy approach; that is, pack as many words as you can in each line. Pad ...
分类:其他好文   时间:2014-06-04 22:37:46    阅读次数:389
HDU2717-Catch That Cow
Farmer John has been informed of the location of a fugitive cow and wants to catch her immediately. He starts at a point N (0 ≤ N ≤ 100,000) on a number line and the cow is at a point K (0 ≤ K ≤ 100,0...
分类:其他好文   时间:2014-06-03 05:30:23    阅读次数:394
【leetcode】 Longest Substring Without Repeating Characters
题目: 给定一个字符串,返回该串没有重复字符的最长子串。 分析: 1)子串:子串要求是连续的。 2)无重复,出现重复就断了,必须从新的位置开始。而新的位置就是重复字符第一次出现位置的下一个位置。 3)整个串可能没有一处重复。 那么,为了找出当前访问的字符是否出现过,要怎么做呢?当然是hash,O(1)的时间,而且既然是字符, 定义个255的hash table 就可以了,has...
分类:其他好文   时间:2014-06-01 10:48:31    阅读次数:206
LeetCode: Merge Sorted Array [088]
【题目】 Given two sorted integer arrays A and B, merge B into A as one sorted array. Note: You may assume that A has enough space (size that is greater or equal to m + n) to hold additional elements from B. The number of elements initialized in A and B are...
分类:其他好文   时间:2014-06-01 09:21:16    阅读次数:292
poj 2769 Reduced ID Numbers(memset使用技巧)
Description T. Chur teaches various groups of students at university U. Every U-student has a unique Student Identification Number (SIN). A SIN s is an integer in the range 0 ≤ s ≤ MaxSIN with MaxS...
分类:其他好文   时间:2014-06-01 07:40:18    阅读次数:248
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