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LeetCode 1:Two Sum
用 Hash Table 实现Time : O(n)Space: O(n)import java.util.HashMap;public class Solution { public int[] twoSum(int[] nums, int target) { HashMap ...
分类:其他好文   时间:2015-10-13 20:54:52    阅读次数:225
单行长度过长显示为省略号
今天get 了css新样式:控制一行一行的文本如果太长,就用省略号显示:样式如下: .myStyle{width:160px;height:50px;line-height:50px;border:4px solid #eee; white-space:nowrap;/*强制文本在一行...
分类:其他好文   时间:2015-10-13 20:49:23    阅读次数:174
Inaccurate values for “Currently allocated space” and “Available free space” in the Shrink File dialog for TEMPDB only
转载自:http://blogs.msdn.com/b/ialonso/archive/2012/10/08/inaccurate-values-for-currently-allocated-space-and-available-free-space-in-the-shrink-file-dia...
分类:数据库   时间:2015-10-13 12:14:55    阅读次数:305
UvaLive 5026 Building Roads
传送门Time Limit: 3000MSDescriptionThere is a magic planet in the space. There is a magical country on the planet. There are N cities in the country. The...
分类:其他好文   时间:2015-10-13 10:25:09    阅读次数:220
More Effective C++ 条款31 让函数根据一个以上的对象类型来决定如何虚化
1. 假设要编写一个发生在太空的游戏,其中有飞船(spaceship),太空站(space station)和小行星(ssteroid),使它们继承自一个抽象基类GameObject,整个继承体系像这样:class GameObject { ... };class SpaceShip: public...
分类:编程语言   时间:2015-10-13 01:38:04    阅读次数:213
Trouble with the Hubble
原文 The Hubble telescope was launched into space by NASA on April 20, 1990 at a cost of over a billion dollars. Right from the start there was trouble with the Hubble. The pictures it sent us were...
分类:其他好文   时间:2015-10-12 14:41:16    阅读次数:300
ocp-323
QUESTION NO: 323 To enable resumable space allocation for the instance, which of the following initialization parameters should you set to a nonzero value? A. RESUMABLE_SPACE_TIME B. RESUMABLE_SPA...
分类:其他好文   时间:2015-10-12 12:43:03    阅读次数:175
The file named error_log is too large
The file named errorlog is too largeThe file named errorlog is too large1 ProblemOne day, when I install android-sdk, I found that one error "NO space...
分类:其他好文   时间:2015-10-11 14:10:17    阅读次数:153
LeetCode Game of Life
原题链接在这里:https://leetcode.com/problems/game-of-life/简单的想法就是copy 原来矩阵,然后根据copy 来修改原来的矩阵,如此做会使用O(m*n) space.如何做到In-space呢,我们需要根据改动前的状态来数出live cell 的个数,已经...
分类:其他好文   时间:2015-10-11 11:28:09    阅读次数:177
POJ 3904(容斥原理)
Sky CodeTime Limit:1000MSMemory Limit:65536KTotal Submissions:1750Accepted:545DescriptionStancu likes space travels but he is a poor software develope...
分类:其他好文   时间:2015-10-11 11:21:51    阅读次数:193
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