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Gorgeous Sequence(线段树)
Gorgeous Sequence Time Limit: 6000/3000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 6946 Accepted Submission(s): ...
分类:其他好文   时间:2019-07-16 16:51:29    阅读次数:125
pOJ 2115
C Looooops Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 35461 Accepted: 10372 Description A Compiler Mystery: We are given a C-language ...
分类:其他好文   时间:2019-07-15 09:15:32    阅读次数:115
poj3045Cow Acrobats
Cow Acrobats Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 7564 Accepted: 2822 Description Farmer John's N (1 <= N <= 50,000) cows (numbe ...
分类:其他好文   时间:2019-07-14 12:48:03    阅读次数:82
HDU 1325 有根树的判断
Is It A Tree? Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 33083 Accepted Submission(s): 7574 ...
分类:其他好文   时间:2019-07-10 14:59:47    阅读次数:106
map
Skip the Class Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1886 Accepted Submission(s): 1045 ...
分类:其他好文   时间:2019-07-09 11:01:32    阅读次数:111
【Poj 2406】Power Strings
Power Strings Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 64676 Accepted: 26679 Description Given two strings a and b we define a*b to ...
分类:其他好文   时间:2019-07-08 10:52:20    阅读次数:95
filter和reduce
this.initdataTables .filter(val => { return val.Accepted === true; }) .reduce(function (total, currentValue, currentIndex, arr) { retur... ...
分类:其他好文   时间:2019-07-01 10:23:53    阅读次数:104
POJ 1276 Cash Machine(完全背包模板题)
Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 44409 Accepted: 16184 Description A Bank plans to install a machine for cash withdrawal. Th ...
分类:系统相关   时间:2019-06-29 12:47:36    阅读次数:117
HDU1024 Max Sum Plus Plus[DP]
Max Sum Plus Plus Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 42745 Accepted Submission(s): 1 ...
分类:其他好文   时间:2019-06-29 11:13:57    阅读次数:85
2019.6.20义乌测试赛自我成绩分析
A. 平均分(average) 提交程序: cpp include using namespace std; char s[1000]; int n; int main() { scanf("%s",s+1); n=strlen(s+1); for(int i=2;i Accepted 100分 ~ ...
分类:其他好文   时间:2019-06-29 10:59:23    阅读次数:105
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