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HDU - 1588 Gauss Fibonacci (矩阵快速幂+二分求等比数列和)
Description Without expecting, Angel replied quickly.She says: "I'v heard that you'r a very clever boy. So if you wanna me be your GF, you should solve the problem called GF~. " How good an oppo...
分类:其他好文   时间:2014-07-29 22:05:52    阅读次数:420
poj 1698 Alice's Chance(网络流)
Alice's Chance Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 5280   Accepted: 2171 Description Alice, a charming girl, have been dreaming of being a movi...
分类:其他好文   时间:2014-07-29 21:53:53    阅读次数:334
Which is the best MongoDB GUI
Which is the best MongoDB GUI?A good UI is an important part of the development experience. The mongo shell works great for administrative actions but...
分类:数据库   时间:2014-07-29 17:17:22    阅读次数:883
LeetCode "Divide Two Integers"
A very interesting numeric problem. It involves a lot tricks.Linear search (by +\-) is not feasible - too slow. So binary search is a good idea. Also ...
分类:其他好文   时间:2014-07-29 14:02:08    阅读次数:187
Localising Variables 局部变量
This tutorial will give a brief overview of the defun function and moreover explain why localising variables is a good habit to get into. By http://le...
分类:其他好文   时间:2014-07-29 13:53:59    阅读次数:136
Get Eco-Bags Are A Great Way To Start
Firstly, they are a very good fit, and a favorite pilot enthusiasts.Vacuuming question is not one of the sexiest do? Home. Therefore, it is important ...
分类:其他好文   时间:2014-07-29 13:29:48    阅读次数:271
ACM训练二B题
这是比赛后打的题目,思路很清晰:申明一个结构体,将输入的数复制在这个结构体数组中,排序后比对下标,找到变动的首下标和尾下标,再看这段是否逆序了。Being a programmer, you like arrays a lot. For your birthday, your friends hav...
分类:其他好文   时间:2014-07-29 11:59:56    阅读次数:267
pig进阶
一个练习:1、student表1:zhangsan:boy:12:compute3:lisi:boy:32:math2:xiaoli:girl:23:meish模式:A = load 'student' using PigStorage(':') as (sno:chararray,sname:ch...
分类:其他好文   时间:2014-07-28 14:57:03    阅读次数:176
URAL - 1057 Amount of Degrees
Description Create a code to determine the amount of integers, lying in the set [ X; Y] and being a sum of exactly K different integer degrees of B. Example. Let X=15, Y=20, K=2, B=2. By...
分类:其他好文   时间:2014-07-28 00:09:39    阅读次数:347
hdu 1850 Being a Good Boy in Spring Festival
我们知道在Nim博弈中 如果我们面对的是一个非奇异局势(a,b,c),要如何变为奇异局势呢?假设 a b)=(a(+)a)(+)(b(+)b)=0(+)0=0。要将c 变为a(+)b,只要从 c中减去 c-( a(+)b)即可。   也就是说,其中一个堆C必须大于所有其他所有堆异或的值,由此我们可以进行枚举 即(sum^a[i])#include int main()...
分类:编程语言   时间:2014-07-27 23:38:10    阅读次数:245
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