1、limits of joins
The maximum number of tables that can be referenced in a single join is 61. This also applies to the number of tables that can be referenced in
the definition of a view.
2、表最多可以有...
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数据库 时间：
2015-05-17 16:50:58
阅读次数：
176
动态规划解决方法：动态规划基本思想（当前N的值由N-1的值推出）class Solution {public:int maxSubArray(int A[], int n) {int res=A[0];int sum=A[0];for(int i=1;i{sum=max(sum+A[i],A[i])...
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其他好文 时间：
2015-05-17 16:30:21
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131
Tree of TreeTime Limit:1 Second Memory Limit:32768 KBYou're given a tree with weights of each node, you need to find the maximum subtree of specified ...
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其他好文 时间：
2015-05-17 12:07:06
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136
题目：Given a binary tree, find its maximum depth.The maximum depth is the number of nodes along the longest path from the root node down to the farthest...
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其他好文 时间：
2015-05-17 00:40:24
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126
Maximum Depth of Binary Tree
Given a binary tree, find its maximum depth.
The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node....
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其他好文 时间：
2015-05-16 20:38:48
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152
Given an unsorted array, find the maximum difference between the successive elements in its sorted form.Try to solve it in linear time/space.Return 0 ...
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其他好文 时间：
2015-05-16 20:03:02
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116
https://leetcode.com/problems/maximum-depth-of-binary-tree/Maximum Depth of Binary TreeGiven a binary tree, find its maximum depth.The maximum depth i...
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编程语言 时间：
2015-05-16 18:11:43
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124
Problem Description
There is a sequence of integers. Your task is to find the longest subsequence that satisfies the following condition: the difference between the maximum element and the minimum ...
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其他好文 时间：
2015-05-16 11:57:35
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127
Find the contiguous subarray within an array (containing at least one number) which has the largest sum. For example, given the array [?2,1,?3,4,?1,2,...
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编程语言 时间：
2015-05-15 10:35:46
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160
Given a binary tree, find its maximum depth.
The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
分析；
此题是求二叉树的深度，（无所谓最大深度），用递归的方法很容...
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其他好文 时间：
2015-05-14 14:18:49
阅读次数：
117
