Given two numbers represented as strings, return multiplication of the numbers as a string.Note: The numbers can be arbitrarily large and are non-nega...
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其他好文 时间:
2015-06-09 15:42:42
阅读次数:
120
题目:Given two numbers represented as strings, return multiplication of the numbers as a string.Note: The numbers can be arbitrarily large and are non-n...
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其他好文 时间:
2015-06-08 19:23:30
阅读次数:
140
In this problem, we are asked to divide two integers. However, we are not allowed to use division, multiplication and mod operations. So, what else ca...
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其他好文 时间:
2015-06-06 23:28:41
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170
UVA442 Matrix Chain Multiplication
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其他好文 时间:
2015-06-05 00:34:48
阅读次数:
116
分析:利用栈处理。遇到矩阵时入栈;遇到“)” 弹出两个矩阵进行运算,并将结果压栈。另外在矩阵相乘时注意两个矩阵是否满足相乘条件。
#include
#include
#include
#include
using namespace std;
#define N 30
struct node
{
char m;
int r,c;
} a[N];
string s;
bool proces...
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其他好文 时间:
2015-06-04 15:53:34
阅读次数:
141
还的确是一个稍有难度博弈的问题(这个可不属于博弈中的任何一个):
题意:游戏规则为:两个人在2-9选数选出之后与p相乘,此时p=p*(2...9);当p>=n时这一方获胜。。
分析:
如果输入是 2 ~ 9 ,(2~9)因为Stan 是先手,所以Stan 必胜
如果输入是 10~18 ,(9+1~9*2)因为Ollie 是后手,不管第一次Stan 乘的是什么...
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其他好文 时间:
2015-06-04 09:58:23
阅读次数:
134
Divide two integers without using multiplication, division and mod operator.比有趣在于1 提速过程 2怎么判断符号正负public class Solution { public int divide(int divi...
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其他好文 时间:
2015-06-02 06:47:51
阅读次数:
91
Description
Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "abcdef". If we think of concatenation as multiplication, exponenti...
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编程语言 时间:
2015-06-01 14:43:30
阅读次数:
254
No.29 Divide Two IntegersDivide two integers without using multiplication, division and mod operator.If it is overflow, return MAX_INT.Tags:MathBinary...
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其他好文 时间:
2015-05-29 15:43:45
阅读次数:
100
描述
Bessie is tired of multiplying pairs of numbers the usual way, so she invented her own style of multiplication. In her style, A*B is equal to the
sum of all possible pairwise products between t...
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其他好文 时间:
2015-05-26 14:29:34
阅读次数:
145