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leetcode:Multiply Strings
Given two numbers represented as strings, return multiplication of the numbers as a string.Note: The numbers can be arbitrarily large and are non-nega...
分类:其他好文   时间:2015-06-09 15:42:42    阅读次数:120
【Multiply Strings】cpp
题目:Given two numbers represented as strings, return multiplication of the numbers as a string.Note: The numbers can be arbitrarily large and are non-n...
分类:其他好文   时间:2015-06-08 19:23:30    阅读次数:140
[LeetCode] Divide Two Integers
In this problem, we are asked to divide two integers. However, we are not allowed to use division, multiplication and mod operations. So, what else ca...
分类:其他好文   时间:2015-06-06 23:28:41    阅读次数:170
UVA442 Matrix Chain Multiplication
UVA442 Matrix Chain Multiplication
分类:其他好文   时间:2015-06-05 00:34:48    阅读次数:116
HDU ACM 1082 Matrix Chain Multiplication
分析:利用栈处理。遇到矩阵时入栈;遇到“)” 弹出两个矩阵进行运算,并将结果压栈。另外在矩阵相乘时注意两个矩阵是否满足相乘条件。 #include #include #include #include using namespace std; #define N 30 struct node { char m; int r,c; } a[N]; string s; bool proces...
分类:其他好文   时间:2015-06-04 15:53:34    阅读次数:141
poj 2505 A multiplication game(博弈)
还的确是一个稍有难度博弈的问题(这个可不属于博弈中的任何一个): 题意:游戏规则为:两个人在2-9选数选出之后与p相乘,此时p=p*(2...9);当p>=n时这一方获胜。。 分析: 如果输入是 2 ~ 9 ,(2~9)因为Stan 是先手,所以Stan 必胜 如果输入是 10~18 ,(9+1~9*2)因为Ollie 是后手,不管第一次Stan 乘的是什么...
分类:其他好文   时间:2015-06-04 09:58:23    阅读次数:134
Divide Two Integers
Divide two integers without using multiplication, division and mod operator.比有趣在于1 提速过程 2怎么判断符号正负public class Solution { public int divide(int divi...
分类:其他好文   时间:2015-06-02 06:47:51    阅读次数:91
POJ2406:Power Strings(后缀数组DC3)
Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "abcdef". If we think of concatenation as multiplication, exponenti...
分类:编程语言   时间:2015-06-01 14:43:30    阅读次数:254
No.29 Divide Two Integers
No.29 Divide Two IntegersDivide two integers without using multiplication, division and mod operator.If it is overflow, return MAX_INT.Tags:MathBinary...
分类:其他好文   时间:2015-05-29 15:43:45    阅读次数:100
ACM-另类乘法
描述 Bessie is tired of multiplying pairs of numbers the usual way, so she invented her own style of multiplication. In her style, A*B is equal to the sum of all possible pairwise products between t...
分类:其他好文   时间:2015-05-26 14:29:34    阅读次数:145
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