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sdut 2610:Boring Counting(第四届山东省省赛原题,划分树 + 二分)
Boring CountingTime Limit: 3000ms Memory limit: 65536K有疑问?点这里^_^题目描述 In this problem you are given a number sequence P consisting of N integer and Pi....
分类:其他好文   时间:2014-05-08 19:17:31    阅读次数:473
Android Scrollview 内部组件android:layout_height="fill_parent"无效的解决办法
Found the solution myself in the end. The problem was not with theLinearLayout,but with theScrollView(seems weird, considering the fact that theScroll...
分类:移动开发   时间:2014-05-08 13:42:02    阅读次数:321
Solving the Detached Many-to-Many Problem with the Entity Framework
IntroductionThis article is part of the ongoing series I’ve been writing recently, but can be read as a standalone article. I’m going to do a better j...
分类:其他好文   时间:2014-05-08 13:01:13    阅读次数:599
python2.7.3 problem:no module name _ssl
本文章參考與:http://www.webtop.com.au/blog/compiling-python-with-ssl-support-fedora-10-2009020237。當我"修"好yum之後就開始修python的ssl問題。我的電腦有python的多個版本。在python2.6.6中...
分类:编程语言   时间:2014-05-08 11:46:52    阅读次数:507
wust-1299-结点选择(树形DP)
Problem Description 有一棵 n 个节点的树,树上每个节点都有一个正整数权值。如果一个点被选择了,那么在树上和它相邻的点都不能被选择。求选出的点的权值和最大是多少? Input 第一行包含一个整数 n 。 接下来的一行包含 n 个正整数,第 i 个正整数代表点 i 的权值。 接下来一共 n-1 行,每行描述树上的一条边。 Out...
分类:其他好文   时间:2014-05-08 04:55:03    阅读次数:282
POJ 1775 sum of Factorial (数论)
链接:http://poj.org/problem?id=1775 Description John von Neumann, b. Dec. 28, 1903, d. Feb. 8, 1957, was a Hungarian-American mathematician who made important contributions to the foundations of m...
分类:其他好文   时间:2014-05-07 23:57:32    阅读次数:402
[ACM] hdu 1285 确定比赛名次 (拓扑排序)
确定比赛名次 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 10358    Accepted Submission(s): 4046 Problem Description 有N个比赛队(1   ...
分类:其他好文   时间:2014-05-07 22:58:01    阅读次数:323
hdu 3006 The Number of set(思维+壮压DP)
The Number of set Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1056    Accepted Submission(s): 655 Problem Description Given you n s...
分类:其他好文   时间:2014-05-07 21:35:32    阅读次数:381
RPG的错排 (HDU 2068)
RPG的错排 Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 6746    Accepted Submission(s): 2738 Problem Description 今年暑假杭电ACM集训队第一次组成女生队,其中...
分类:其他好文   时间:2014-05-07 15:59:59    阅读次数:366
POJ1141 Brackets Sequence (dp动态规划,递归)
本文出自:http://blog.csdn.net/svitter 原题:http://poj.org/problem?id=1141 题意:输出添加括号最少,并且使其匹配的串。 题解: dp [ i ] [ j ] 表示添加括号的个数, pos[ i][ j ] 表示i, j中哪个位置分开,使得两部分分别匹配。 初始值置dp [ i ] [ i ]  = 1; 如果只有一个括号,...
分类:其他好文   时间:2014-05-07 15:17:21    阅读次数:367
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